I NEED HELP ON THIS QUESTION!

How do two objects at different temperatures attain thermal equilibrium?

Lady bird [3.3K]

Answer:

C.As the two objects touch, thermal energy flows as heat from the warmer block to the colder block until particles in both blocks move at the same rate and reach the same temperature.

Explanation:

Heat is the transfer of thermal energy from an object at higher temperature to an object at colder temperature.

The temperature of an object is a measure of how fast the particles in the object move: the higher its temperature, the faster the particles move, the higher the average kinetic energy of the particles in the object. As a result, the particles of the object at higher temperature tend to transfer more energy (called thermal energy) to the particles of the object at colder temperature by colliding with them: this process continues until the particles of the colder object reach the same average kinetic energy as the particles of the warmer object, and this means that the two objects have reached the same temperature.

3 0

3 years ago

There are both enviromental and food stimuli that can disrupt sleep true or false

konstantin123 [22]

The answer is true. I hope that this helps you out!!

4 0

2 years ago

iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weig

Alika [10]

Answer:

453 gm

Explanation:

<u>Immersed </u>objects are buoyed up by force equal to mass of displaced liquid

400 + 53 = 453 gm in air

8 0

1 year ago

A team of seven psychologist is study love, but each psychologist is working from a different perspective. In your opinion, what

stepladder [879]

Answer:

- Behavioral Psychologists

- Psychodynamic Psychologist

- Biological Psychologist

- Cognitive Psychologist

- Evolutionary Psychologist

- Socio - Cultural Psychologist

- Humanist Psychologist

Explained in explanation section

Explanation:

There are different classes of psychologists but for the purpose of this question we need just 7 that would fit into the study of love. These 7 will be;

1) A behavioral Psychologist might study behaviors associated with love, such as hugging, caressing or kissing.

2) A psychodynamic psychologist might study how a people's challenges with love are caused by unmindful and unresolved conflicts.

3) A biological psychologist might study which chemicals in the brain such as dopamine make people feel loved. He might also study parts of the what parts of the brain are active when people are in love.

4) A cognitive psychologist might study how people's cognitive processes will change when they are in love.

5) An evolutionary psychologist might study how certain actions or behaviors associated with love provided our forefathers with sufficient knowledge to handle their love problems.

6) A sociocultural psychologist might study how people express love in in various cultures across the world.

7) A humanistic psychologist might study the behavior of those who feel most loved and the impact it has in their lives

8 0

3 years ago

A proton and an alpha particle are momentarily at rest at adistance r from each other. They then begin to move apart.Find the sp

Arte-miy333 [17]

Answer:

The unknown quantities are:

E and F

The final velocity of the proton is:

√(8/3) k e^2/(m*r)

Explanation:

Hello!

We can solve this problem using conservation of energy and momentum.

Since both particles are at rest at the beginning, the initial energy and momentum are:

Ei = k (q1q2)/r

pi = 0

where k is the coulomb constant (= 8.987×10⁹ N·m²/C²)

and q1 = e and q2 = 2e

When the distance between the particles doubles, the energy and momentum are:

Ef = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

pf = m1v1 + m2v2

with m1 = m, m2 = 4m, v1=vf_p, v2 = vf_alpha

The conservation momentum states that:

pi = pf

Therefore:

m1v1 + m2v2 = 0

That is:

v2 = (1/4) v1

The conservation of energy states that:

Ei = Ef

Therefore:

k (q1q2)/r = k (q1q2)/2r + (1/2)m1v1^2 + (1/2)m2v2^2

Replacing

m1 = m, m2 = 4m, q1 = e, q2 = 2e

and v2 = (1/4)v1

We get:

(1/2)mv1^2 = k e^2/r + (1/2)4m(v1/4)^2 = k e^2/r + (1/8)mv1^2

(3/8) mv1^2 = k e^2/r

v1^2 = (8/3) k e^2/(m*r)

3 0

3 years ago