I NEED HELP ON THIS QUESTION!
1 answer:
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Answer:
Explanation:
Given that,
The magnitude of magnetic field, B = 0.55 T
The radus of the loop, r = 43 cm = 0.43 m
The current in the loop, I = 5.8 mA = 0.0058 A
We need to find the magnetic moment of the loop. It is given by the relation as follows :
Put all the values,
So, the magnetic moment of the loop is equal to.
The re<span>sistance of the second wire is 16 R.
where R is the resistance of the first wire.
R = </span>ρ
where l = length of the wire
A = area of the wire
A =
where, r = 
Thus, on finding the ratio of resistance of the two wires, we get,
here, R1 = R
l1 = 8m
l2 = 2m
A1=π
A1=π
we get. R2 = 16R
where R is the resistance of the first wire.
R = </span>ρ
where l = length of the wire
A = area of the wire
A =
Thus, on finding the ratio of resistance of the two wires, we get,
here, R1 = R
l1 = 8m
l2 = 2m
A1=π
A1=π
we get. R2 = 16R