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Brrunno [24]
3 years ago
9

a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​

Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, a_c, is given as follows;

a_c = \dfrac{v^2}{r}

Therefore, the centripetal acceleration of the stone found as follows;

a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2

The centripetal acceleration of the stone, a_c = 5 m/s².

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solong [7]

To solve this problem we will apply the concepts related to the Doppler Effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other.

Mathematically it can be described as

v' = v (\frac{f' ( v - v_{bat}) - f ( v + v_{bat})}{f'(v-v_{bat}) + f ( v + v_{bat})})

Where,

v = Speed of sound

f' = Reflected frequency

f = Emitted Frequency

v_{bat} = Speed of the object

Assuming that the speed of the medium is the speed of sound of 343m / s, we will then have that:

v' = 343 (\frac{(83.5) (343 -3.9) - 80.2(343+3.9)}{83.5(343-3.9) + 80.2(343+4.3)})

v' = 3.0134m/s

8 0
3 years ago
There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?
Lemur [1.5K]

Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

<h3>Definition of current</h3>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

<h3>Definition of voltage</h3>

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

<h3>Definition of resistance</h3>

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

<h3>Ohm's law</h3>

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

I=\frac{V}{R}

Where:

  • I is the current measured in amps (A).
  • V the voltage measured in volts (V).
  • R the resistance that is measured in ohms (Ω).

<h3>Resistance of the lightbulb</h3>

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

0.83A=\frac{120 V}{R}

Solving:

0.83 A× R=  120 V

R=\frac{120 V}{0.83A}

<u><em>R= 144.58 Ω</em></u>

Finally, the resistance of the lightbulb is 144.58 Ω.

Learn more about Ohm's law:

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3 0
2 years ago
HELPPP PLS BESTIES A pattern of stars that has been named is called a constellation. One winter evening, Jason found the star ca
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Answer:

D) Since the stars would move from East to West just as the Sun and Moon do.

5 0
3 years ago
An airliner arrives at the terminal, and its engines are shut off. The rotor of one of the engines has an initial clockwise angu
Ilia_Sergeevich [38]

(a) 1200 rad/s

The angular acceleration of the rotor is given by:

\alpha = \frac{\omega_f - \omega_i}{t}

where we have

\alpha = -80.0 rad/s^2 is the angular acceleration (negative since the rotor is slowing down)

\omega_f is the final angular speed

\omega_i = 2000 rad/s is the initial angular speed

t = 10.0 s is the time interval

Solving for \omega_f, we find the final angular speed after 10.0 s:

\omega_f = \omega_i + \alpha t = 2000 rad/s + (-80.0 rad/s^2)(10.0 s)=1200 rad/s

(b) 25 s

We can calculate the time needed for the rotor to come to rest, by using again the same formula:

\alpha = \frac{\omega_f - \omega_i}{t}

If we re-arrange it for t, we get:

t = \frac{\omega_f - \omega_i}{\alpha}

where here we have

\omega_i = 2000 rad/s is the initial angular speed

\omega_f=0 is the final angular speed

\alpha = -80.0 rad/s^2 is the angular acceleration

Solving the equation,

t=\frac{0-2000 rad/s}{-80.0 rad/s^2}=25 s

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3 years ago
A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire
soldi70 [24.7K]

Answer:

a)  v=4.0m/s

b)  B=2.958T

Explanation:

From the question we are told that:

Wire Length l=10cm=>0.10m

Resistance R=0.35

Force F=1.0N

Power P=4.0W

a)

Generally the equation for Power is mathematically given by

P=Fv

Therefore

v=\frac{P}{F}

v=\frac{4.0}{1.0}

v=4.0m/s

b)

Generally the equation for Magnetic Field is mathematically given by

B=\frac{\sqrt{PR}}{vl}

B=\frac{\sqrt{4*0.35}}{4*0.10}

B=2.958T

5 0
3 years ago
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