1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
9

a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​

Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, a_c, is given as follows;

a_c = \dfrac{v^2}{r}

Therefore, the centripetal acceleration of the stone found as follows;

a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2

The centripetal acceleration of the stone, a_c = 5 m/s².

You might be interested in
Help me please........................
stepan [7]

Answer:

Left

Explanation:

3 0
2 years ago
A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0
3 years ago
A 25 N force stretches a spring 280 cm. What was the spring constant? ​
boyakko [2]

Answer:

  1. F= 25N
  2. ∆l=280cm
  3. K=?
  4. you apply the formula = K:F/∆l
  5. = 0,089N/cm
4 0
2 years ago
Read 2 more answers
Which is the best example of Newton's First Law of Motion? A small, lightweight ball and a large, heavy ball are dropped off the
Marizza181 [45]
I believe the best example of Newton's First Law of motion would be the example or illustration with the basketball player. An object will move in a straight line or a given direction at a constant speed unless or until another force acts upon the object, causing a change in speed and or direction.
4 0
3 years ago
Read 2 more answers
A hollow spherical shell has mass 8.20 kg and radius 0.220 m. It is initially at rest and then rotates about a stationary axis t
Likurg_2 [28]

Answer:

8.91 J

Explanation:

mass, m = 8.20 kg

radius, r = 0.22 m

Moment of inertia of the shell, I = 2/3 mr^2

                                                    = 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2

n = 6 revolutions

Angular displacement, θ = 6 x 2 x π = 37.68 rad

angular acceleration, α = 0.890 rad/s^2

initial angular velocity, ωo = 0 rad/s

Let the final angular velocity is ω.

Use third equation of motion

ω² = ωo² + 2αθ

ω² = 0 + 2 x 0.890 x 37.68

ω = 8.2 rad/s

Kinetic energy,

K = \frac{1}{2}I\omega ^{2}

K = 0.5 x 0.265 x 8.2 x 8.2

K = 8.91 J

6 0
3 years ago
Other questions:
  • Describe how wavelength, frequency, and energy are related.
    8·1 answer
  • Which of the following does NOT influence one's body composition? A. metabolism B. financial problems C. childhood obesity D. me
    5·2 answers
  • How do objects and substances have kinetic energy??<br><br> I need help ASAP!!
    7·1 answer
  • To maintain the same amount of torque due to a mass on a balance as the mass is increased, how should the position of the mass c
    5·1 answer
  • Two narrow, parallel slits separated by 0.850 mm are illuminated by 600-nm light, and the viewing screen is 2.80 m away from the
    13·1 answer
  • What is the net force required to accelerate a 884 kg car at 2 m/sec2?
    6·1 answer
  • You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp
    14·1 answer
  • Which is the correct order of events in the water cycle?
    8·1 answer
  • An alarm clock is dropped off the edge of a tall building. You, standing directly under it, hear a tone of 1350 Hz coming from t
    15·1 answer
  • The duration between the emission of the sound from the echo reception is: t - 1.5 s. the distance between the observer and the
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!