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2 years ago

Two gravitational forces act on a

Physics

1 answer:

Alik [6]2 years ago

3 0

Answer:

Explanation:

Depends on the location of the two forces. If they are aligned on the same side of the object, you would simply add.

X -----------F1 -------F2

X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2

If they are are on either side of the object, you subtract.

F1 ---------X ---------F2

Fx = F1 - F2

Any other location of F1 and F2 is much more complicated by the use of trigonometry.

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If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly

mariarad [96]

Option A because those are the correct ones

4 0

1 year ago

Calculate the kinetic energy that the earth has because of (a) its rotation about its own axis and (b) its motion around the sun

Dominik [7]

Answer:

a. $K_{Axis}=2.574x10^{29}J$

b. $K_{Orbit}=2.6577x10^{33}J$

Explanation:

$K_{Axis}=\frac{1}{2}I*w^2$

$I_{Sphere}=\frac{2}{5}*m*r^2$

$w=\frac{2\pi }{T}$ , $T=24hrs*\frac{3600s}{1hr} =86400s$

radius earth = 6371 km

mass earth = 5,972*10^24 kg

$K_{Axis}=\frac{1}{2}*\frac{2}{5}*m*r^2*(\frac{2\pi}{T})^2$

$K_{axis}=\frac{4\pi^2}{5}*5.98x10^{24}kg*(6.38x10^6m)^2*(\frac{1}{86400s})^2$

$K_{Axis}=2.574x10^{29}J$

$T=1year*\frac{365day}{1year}*\frac{24hr}{1day}*\frac{3600s}{1hr}=31536000s$

$K_{Orbit}=\frac{1}{2}*I*w$

$I=m*r^2$

$K_{Orbit}=\frac{1}{2}*m*r^2*(\frac{2\pi}{T})^2$

$K_{Orbit}=\frac{4\pi^2}{5}*5.98x10^{24}*6.38x10^6m*(\frac{1}{31.536x10^6s})^2$

$K_{Orbit}=2.6577x10^{33}J$

4 0

3 years ago

Interactive Solution 9.1 presents a model for solving this problem. The wheel of a car has a radius of 0.300 m. The engine of th

Murrr4er [49]

Answer:

740 N

Explanation:

We are given that

Radius,r=0.3 m

Torque, $\tau=222 Nm$

We have to find the magnitude of the static frictional force.

According to question

Torque by engine=Torque by static friction

$222=f\times r$

$f=\frac{222}{r}$

$f=\frac{222}{0.3}$

$f=740 N$

Hence, the magnitude of static frictional force=740 N

8 0

2 years ago

Before a ball rolls down a hill, it has gravitational potential energy. Before a rubber ball bounces away from a surface, it has

rjkz [21]

Answer:

human potential energy

Explanation:

It is given that, before a ball rolls down a hill, it has gravitational potential energy.

Before a rubber ball bounces away from a surface, it has elastic potential energy.

Human potential energy allows us to throw a ball. While throwing a ball, we have to apply some force by our muscles in order to done some work.Also, we know that the capacity to do work is called energy.

Hence, the correct option is (D) " human potential energy ".

5 0

2 years ago

Read 2 more answers

Calcular la fuerza que un campo magnético de 4x10-5 T ejerce sobre una carga eléctrica de +3uC que se mueve perpendicularmente a

Gennadij [26K]

English sorry that all English plz

7 0

2 years ago