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2 years ago

Two gravitational forces act on a

Physics

1 answer:

Alik [6]2 years ago

3 0

Answer:

Explanation:

Depends on the location of the two forces. If they are aligned on the same side of the object, you would simply add.

X -----------F1 -------F2

X is the object. F1 and F2 are both masses which create a gravitational force. They both are the form of Fx = G * m1 * m2 / r^2. The total force is F1 + F2

If they are are on either side of the object, you subtract.

F1 ---------X ---------F2

Fx = F1 - F2

Any other location of F1 and F2 is much more complicated by the use of trigonometry.

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You are part of a design team assigned the task of making an electronic oscillator that will be the timing mechanism of a micro-

Snowcat [4.5K]

Solution :

We assume that there is a ring having a charge +Q and radius r. Electric field due to the ring at a point P on the axis is given by :

$E_P=\int dE \cos$

$E_P=\int \frac{KdQ}{(\sqrt{r^2+x^2})^2}\times \frac{x}{\sqrt{r^2+x^2}}$

$\vec{E_P}=\frac{Kx}{r^2+x^2} \int dQ$

$\vec{E_P}=\frac{KxQ}{(r^2+x^2)^{3/2}} \hat{i}$

If we put an electron on point P, then force on point e is :

$\vec{F}=-|e|\vec{E_P}$

$F= \frac{-eKQx}{(r^2+x^2)^{3/2}}= \frac{-eKQx}{r^3[1+\frac{x^2}{r^2}]^{3/2}}$

If r >> x , then $\frac{x^2}{r^2} \approx 0$

Then, $\frac{-eKQ}{r^3}x$

$ma =\frac{-eKQ}{r^3}x$

$a =\frac{-eKQ}{mr^3}x$

Compare, a = -ω²x

We get,

$\omega^2 = \frac{eKQ}{R^3m}$

$\omega = \sqrt{\frac{eKQ}{r^3m}}$

$2 \pi f = \sqrt{\frac{eKQ}{r^3m}}$

$f = \frac{1}{2 \pi}\sqrt{\frac{eKQ}{mr^3}}$

6 0

3 years ago

Christian made some pancakes she's so 3/5 of them in the morning and 1/4 of the remainder in the afternoon is she had 300 pancak

DiKsa [7]

Christian made 1000 pancakes.

Explanation:

Let us represent the total amount of Pancake made by Christian as = K

From the problem;

Christian ate $\frac{3}{5}$ of the pancake in the morning = $\frac{3}{5}$ * K = $\frac{3}{5}$ K

We know that Christian cannot eat her pancake and at the same time have it, the remaining pancake will then be:

total amount of cake - fraction eaten

Remainder = K - $\frac{3}{5}$ K= $\frac{2}{5}$ K

In the afternoon, we know that she ate 1/4 of the remaining cake:

$\frac{1}{5}$ K* $\frac{2}{5}$ K = $\frac{1}{10}$ K

The remaining cake in the afternoon will be:

Total amount of cake remaining from morning - amount eaten in the afternoon

= $\frac{2}{5}$ K - $\frac{1}{10}$ K

= $\frac{3}{10}$ K

The fraction of the cake remaining in the afternoon is $\frac{3}{10}$ K

Since she had 300cakes left in the afternoon, then :

$\frac{3}{10}$ K= 300

K = 1000 pancakes

Therefore Christian made 1000 pancakes.

learn more:

Fractions brainly.com/question/1648978

#learnwithBrainly

4 0

3 years ago

A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300

IrinaVladis [17]

Answer:

The bottom of the sea is 25 m below sea level.

Explanation:

Given data

Mass = 6.1 × $10^{8} \ kg$

$\rho_{sea} = 1020\ \frac{kg}{m^{3} }$

We know that Buoyant force on the tank is equal to gravity force of the tank.

$F_B = F_g$

$(\rho_{Fluid}) (g) (V_{disp}) = m g$

$(\rho_{Fluid}) (V_{disp}) = m$

1020 × $V_{disp}$ = 6.1 × $10^{8}$

$V_{disp}$ = 598039.21 $m^{3}$

We know that

$V_{disp}$ = W × L × H

598039.21 = 300 × 80 × H

H = 25 m

Therefore the bottom of the sea is 25 m below sea level.

7 0

3 years ago

What property of light waves does the michelson-morley interferometer directly demonstrate?

yan [13]

The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.

8 0

3 years ago

What would make oppositely charged objects attract each other more? increasing the positive charge of the positively charged obj

kykrilka [37]

Answer:

Explanation:

I did the test :D

3 0

3 years ago

Read 2 more answers