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navik [9.2K]
3 years ago
14

Which scientist developed the 1st model of the atom that showed the structure of the inside of an atom?

Chemistry
1 answer:
frez [133]3 years ago
7 0
C. Rutherford (1911)
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Ag+(aq) + e- → Ag(s) E° = +0.800 V AgBr(s) + e- → Ag(s) + Br-(aq) E° = +0.071 V Br2(l) + 2 e- → 2 Br-(aq) E° = +1.066 V Use some
Gekata [30.6K]

Answer:

k_{sp}=4.7 \times 10^{-13}.

Explanation:

Now equation of tqo halves are:

Oxidation : Ag(s)-->Ag^+(aq)+e^-

Reduction : AgBr(s)+e^--->Ag(s)+Br^-(aq)

We know,

E^o_{cell}=0.071-(0.8)=-0.729\ V.

\Delta G^o=-n\times F \times E^o= -R\times T\times ln(k_s_p)\\-1\times 96485\times (-0.729)=-8.314\times 298\times ln(k_s_p)\\k_s_p=4.7\times 10^{-13}.

k_{sp}=4.7 \times 10^{-13}.

Hence, this is the required solution.

5 0
3 years ago
After use, non-biodegradable plastics last for many years in __________ sites. Many also pollute the ocean.
Len [333]

Answer:

Land fill

Explanation:

A landfill is a carefully managed waste disposal site. It is the oldest method of waste disposal. In a dumpsite, biodegradable materials decay overtime.

However, non-biodegradable materials such as plastics and other polymers tend to last many years in landfills. This category of wastes pose a great threat to the environment.

7 0
3 years ago
What volume will 1.12 moles of nitrogen gas occupy at STP
krok68 [10]

Answer:

Explanation:

Volume occupied by Nitrogen gas at STP = number of moles x 22.4dm³/mol

Number of moles = 1.12moles

Volume = 1.12 x 22.4

Volume at STP = 25.1dm³

8 0
4 years ago
True or false: scientists make observations very carefully<br> science
Olenka [21]
True, scientists do make observations very carefully.
3 0
4 years ago
Read 2 more answers
A 101.2 ml sample of 1.00 m naoh is mixed with 50.6 ml of 1.00 m h2so4 in a large styrofoam coffee cup; the cup is fitted with a
Murrr4er [49]

The enthalpy change of the reaction when sodium hydroxide and sulfuric acid react can be calculated using the mass of solution, temperature change, and specific heat of water.

The balanced chemical equation for the reaction can be represented as,

H_{2}SO_{4}(aq) + 2NaOH (aq) ----> Na_{2}SO_{4}(aq) + 2H_{2}O(l)

Given volume of the solution = 101.2 mL + 50.6 mL = 151.8 mL

Heat of the reaction, q = m C .ΔT

m is mass of the solution = 151.8 mL * \frac{1 g}{1 mL} = 151.8 g

C is the specific heat of solution = 4.18 \frac{J}{g. ^{0}C}

ΔT is the temperature change = 31.50^{0}C - 21.45^{0}C = 10.05^{0}C

q = 151.8 g (4.18 \frac{J}{g ^{0}C})(10.05^{0}C) = 6377 J

Moles of NaOH = 101.2 mL * \frac{1L}{1000 mL}*\frac{1.00 mol}{L} = 0.1012 mol NaOH

Moles of H_{2}SO_{4} = 50.6 mL * \frac{1 L}{1000 mL} * \frac{1.0 mol}{1 L} = 0.0506 mol H_{2}SO_{4}

Enthalpy of the reaction = \frac{6377 J*\frac{1kJ}{1000J}}{0.0506 mol} = 126 kJ/mol

5 0
3 years ago
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