Which scientist developed the 1st model of the atom that showed the structure of the inside of an atom?

Substituents on an aromatic ring can have several effects on electrophilic aromatic substitution reactions. Substituents can act

Leya [2.2K]

Answer:

Option A=> -NHCOCH3 and option C = -CH3.

Explanation:

The option A that is -NHCOCH3 is CORRECT because it possesses lone pair of electron with the exception of group 7A elements. It is this lone pair that is used in the Activation of the ring towards substitution. Other groups that falls into this group are; OCH3, alkyls and many others.

Option B that is -COOH is good group for withdrawal of electron through Resonance. Other examples are NO2, -CN and SO3H.

Option C falls to the same category as option A above that is Activation of the ring towards substitution.

Option D falls to the same category as option B above that is group for withdrawal of electron through Resonance.

7 0

3 years ago

A local meteorologist reports the days weather. Which information is qualitative? Check all that apply.

Leokris [45]

A meterologist studies weather

3 0

3 years ago

Help me for brainlest pleaes

Tresset [83]

First option.

The male tails are more attractive because of their long feathers , meanwhile the female tails are shorter than expected!

6 0

3 years ago

If you travel 7.5 km and walk for 1.5 h, what is your average speed? <br> Show your work?

Assoli18 [71]

Answer: 5
Explanation: you divide the distance by the time and get the speed.

3 0

3 years ago

For the following reaction, KcKc = 255 at 1000 KK.

bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

Initial conc. 0.1550 0.173 0

At eqm. (0.1550-x) (0.173-x) x

As we are given:

$K_c=255$

The expression for equilibrium constant is:

$K_c=\frac{[COCl_2]}{[CO][Cl_2]}$

Now put all the given values in this expression, we get:

$255=\frac{(x)}{(0.1550-x)\times (0.173-x)}$

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0

3 years ago