Answer:
Chemical equation: NH₃(g) + O₂(g) → NO(g) + H₂O(l).
Oxidation reaction: N⁻³ → N⁺² + 5e⁻ /×4.
Reduction reaction: O₂⁰ + 4e⁻ → 2O⁻² /×5.
Oxidation reaction: 4N⁻³ → 4N⁺² + 20e⁻.
Reduction reaction: 5O₂⁰ + 20e⁻ → 10O⁻² /×5.
Balanced chemical equation: 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l).
Ammonia (NH₃) reacts with oxygen (O₂) and form nitrogen(II) oxide (NO) and water (H₂O). Catalyst is this reaction is platinum (Pt).
This is combustion reaction.
Answer:
a) pH will be 12.398
b) pH will be 4.82.
Explanation:
a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles
The total volume after addition of pure water = 0.780+0.01 = 0.79 L
The new concentration of /NaOH will be:

the [OH⁻] = 0.025
pOH = -log [OH⁻] = 1.602
pH = 14 -pOH = 12.398
b) The buffer has butanoic acid and butanoate ion.
i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:
![pH=pKa+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
pKa=
ii) on addition of base the pH will increase.