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navik [9.2K]
3 years ago
14

Which scientist developed the 1st model of the atom that showed the structure of the inside of an atom?

Chemistry
1 answer:
frez [133]3 years ago
7 0
C. Rutherford (1911)
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Enter an equation to show how h2po3− can act as a base with hs− acting as an acid. Express your answer as a chemical equation. I
vladimir2022 [97]

The acid - base equation between H2PO3^- and HS^- is H2PO3^- +  HS^- ⇄S^- + H3PO3.

<h3>What is an acid?</h3>

An acid is a substance that can donate hydrogen ions while a base is a substance that can accept hydrogen ion. This is the acid base definition according to Brownstead - Lowry.

To show the acid - base relationship between H2PO3^- and HS^-, we have the equation;

H2PO3^- +  HS^- ⇄S^- + H3PO3

Learn more about acids and bases: brainly.com/question/10282816

4 0
1 year ago
Solid-solid homogeneous mixture give one example
likoan [24]
Example of solid - solid homogeneous mixture is copper metal - silver metal like coins and alloys. Homogeneous mixture is a mixture in which one of the substances often changes in form as in a solution of sugar in water. It contains variable proportions. Solution can contain two substances, three substances or more, in a single physical state. The component of a solution that is present in greatest quantity is usually called the solvent and all other components are called solutes.
5 0
3 years ago
Read 2 more answers
Many insulating materials contain spaces filled with air because air is what type of material?
Rina8888 [55]
<span>It is because air is a poor conductor of heat. Good luck ;)</span>
6 0
3 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

7 0
3 years ago
Can you do my project please and I'll mark brainllest
Alex17521 [72]

Answer:

Whats the project?

Explanation:

8 0
3 years ago
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