Answer:
Density independent factor
Explanation:
in dense areas where people livein very close and tight spaces
Answer:
Mass of liquid: 20.421g
Density= 1.0109405940594 g/mL
Explanation:
Mass of liquid
To find mass of liquid you take the mass of beaker + liquid (171.223g) and subtract it from the Mass of beaker (beaker without the water). The difference is the answer.
171.223g - 150.802g = 20.421g
Density
To find density you use the formula Mass/Volume. Take the Volume given, and the mass of the liquid you just found.
20.421mL/20.421g = 1.0109405940594 g/mL
Ideal behavior is approached by gases when the conditions of the system are at a low pressure and high temperatures. Therefore, the correct answer is C. At the conditions of lowest temperature highest pressure, gases will deviate from an ideal gas.
Answer:

Explanation:
It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.
Then you can consider it to be 11018 "moles" of "kJ"
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32.00
2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ
n/mol: 7280
1. Moles of O₂
The molar ratio is 25 mol O₂:11 018 kJ

2. Mass of O₂

Answer:
1.33 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and T are constant, and have different values of P and V:
<em>(P₁V₁) = (P₂V₂)</em>
<em></em>
Knowing that:
V₁ = 4.0 L, P₁ = 2.0 atm,
V₂ = ??? L, P₂ = 6.0 atm.
- Applying in the above equation
(P ₁V₁) = (P₂V₂)
<em>∴ V₂ = P ₁V₁/P₂</em> = (2.0 atm)(4.0 L)/(6.0 atm) =<em> 1.33 L.</em>