Which power source directs the electrons from oxidation-reduction reactions to flow through a device to give the device power? O
1 answer:
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Answer:
All three are present
Explanation:
Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble: .
- Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
- Secondly, addition of liquid ammonia would form a precipitate with silver:
; Silver hydroxide at higher temperatures decomposes into black silver oxide:
.
- Thirdly, we also know we have
in the mixture, since addition of potassium chromate produces a yellow precipitate:
. The latter precipitate is yellow.
Answer and explanation:
cyclopentadiene is more acidic than cyclopentane
hydrocarbon compound are weak acid in nature
This relative acidity is explained by the stability of
cyclopentadienyl anion which is aromatic in nature
(check the attached image file 1)
To answer this question we must look at the stability of the anions that are formed when the compound lose proton.
All the electron in the cyclopentyl anion are localized.
In contrast, the aromatic cyclopentadienyl anion is a stable carbanion as a result of its aromaticity therefore making its conjugate acid a very strong acid compare to other compounds with hydrogen attached to sp³ carbons
