Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2 </span> We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:
120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed
Answer:An increase in temperature commonly will increase the rate of reaction. An growth in temperature will improve the common kinetic electricity of the reactant molecules.
