Answer:
The correct answer is 2.016 x 10⁻¹⁷
Explanation:
We have the following chemical reactions and their equilibrium constants (K):
(1) H₂CO₃(aq) + H₂O ⇒ H₃O⁺(aq) + HCO₃⁻(aq) K₁= 4.20×10⁻⁷
(2) HCO₃⁻(aq) + H₂O ⇒ H₃O⁺(aq) + CO₃²⁻(aq) K₂= 4.80×10⁻¹¹
And we have to obtain K for the following reaction:
H₂CO₃(aq) + 2H₂O ⇒ 2H₃O⁺(aq) + CO₃²⁻(aq)
If we add equations (1) and (2) we obtain the the desired equation. Remember that when we add chemical equations, the global equilibrium constant is the product of the constants.
H₂CO₃(aq) + H₂O ⇒ H₃O⁺(aq) + <em><u>HCO₃⁻(aq)</u></em> K₁= 4.20×10⁻⁷
+
<em><u>HCO₃⁻(aq)</u></em> + H₂O ⇒ H₃O⁺(aq) + CO₃²⁻(aq) K₂= 4.80×10⁻¹¹
-------------------------------------------------------------
H₂CO₃(aq) + 2H₂O ⇒ 2H₃O⁺(aq) + CO₃²⁻(aq) K= K₁ x K₂
K = K₁ x K₂ = (4.20×10⁻⁷) x (4.80×10⁻¹¹) = 2.016 x 10⁻¹⁷
Answer:regular variation in magnitude or position around a central point. Or movement back and forth at a regular speed
Explanation:
4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
<h3>What are Noble Gases ?</h3>
The noble gases are helium, argon, krypton, xenon, and radon, in order of their mass.
They are called noble gases because they are so majestic that they do not react with anything in general.
The work done can be calculated by the formula
Q=n Cp ΔT
Cp= ( 1+ f/2)R
R= 8.3144598 J. mol-1.
Cp = (1+3/2) * 8.314
Cp = 5*8.314/2
Q= 2 * 5 *8.314 *100/2
Q = 4157 J
Therefore 4157 J work is done by the gas , If 2 moles of helium undergo a temperature increase of 100 K at constant pressure.
To know more about Noble Gas
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Answer:
Light and sound both are waves, but sound requires a material medium to travel, and hence cannot travel in empty space while light can travel through vacuum but not through opaque materials. Both undergo refraction, diffraction and interference.
Explanation: