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Brilliant_brown [7]
4 years ago
15

Why is it important that plants have water available in their environment?

Chemistry
2 answers:
PolarNik [594]4 years ago
4 0

Answer:

Water is essential in order for a plant to grow.

Explanation:

Water is an essential part of the plant slife cycle so without itthe plant would not be able to grow and die.

katen-ka-za [31]4 years ago
3 0

Answer:

so they can grow

Explanation:

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Two moles of ideal He gas are contained at a pressure of 1 atm and a temperature of 300 K. 34166 J of heat are transferred to th
iragen [17]

Explanation:

The given data is as follows.

       n = 2 mol,         P = 1 atm,         T = 300 K

        Q = +34166 J,         W= -1216 J (work done against surrounding)

       C_{v} = \frac{3R}{2}

Relation between internal energy, work and heat is as follows.

      Change in internal energy (\Delta U) = Q + W

                                   = [34166 + (-1216)] J

                                   = 32950 J

Also,  \Delta U = n \times C_{v} \times \Delta T

                      = 3R \times (T_{2} - T_{1})

                 32950 J = 3 \times 8.314 J/mol K \times (T_{2} - 300 K)

                \frac{32950}{24.942} = T_{2} - 300 K

                            1321.06 K + 300 K = T_{2}    

                                       T_{2} = 1621.06 K

Thus, we can conclude that the final temperature of the gas is 1621.06 K.

8 0
3 years ago
Can someone tell me the answer ?
ludmilkaskok [199]
The Aufbau principle states that, hypothetically, electrons orbiting one or more atoms fill the lowest available energy levels before filling higher levels (e.g., 1s before 2s). In this way, the electrons of an atom, molecule, or ion harmonize into the most stable electron configuration possible.
7 0
3 years ago
What is the wavelength of light that has a frequency of 3.7 x 1014 Hz? Show all work!!!
kramer

Answer:

Explanation:

f=\frac{c}{\lambda}=>\lambda=\frac{c}{f}=\frac{300x10^8\frac{m}{s}}{3.7*10^{14}\frac{1}{s}}=810.8108*10^{-9}m

3 0
3 years ago
Read 2 more answers
The following reactions can be used to prepare samples of metals. Determine the enthalpy change under standard state conditions
mamaluj [8]

Answer:

a) 62.1 kJ/mol

b) 2.82 kJ/mol

c) 270.91 kJ/mol

d) -851.5 kJ/mol

Explanation:

The enthalpy change for a reaction in standard conditions (ΔH°rxn) can be calculated by:

ΔH°rxn = ∑n*ΔH°f, products - ∑n*ΔH°f, reagents

Where n is the number of moles in the stoichiometry reaction, and ΔH°f is the enthalpy of formation at standard conditions. ΔH°f = 0 for substances formed by only a single element. The values can be found in thermodynamics tables.

a) 2Ag₂O(s) → 4Ag(s) + O₂(g)

ΔH°f, Ag₂O(s) = -31.05 kJ/mol

ΔH°rxn = 0 - (2*(-31.05)) = 62.1 kJ/mol

b) SnO(s) + CO(g) → Sn(s) + CO₂(g)

ΔH°f,SnO(s) = -285.8 kJ/mol

ΔH°f,CO(g) = -110.53 kJ/mol

ΔH°f,CO₂(g) = -393.51 kJ/mol

ΔH°rxn = [-393.51] - [-110.53 - 285.8] = 2.82 kJ/mol

c) Cr₂O₃(s) + 3H₂(g) → 2Cr(s) + 3H₂O(l)

ΔH°f,Cr₂O₃(s) = -1128.4 kJ/mol

ΔH°f,H₂O(l) = -285.83 kJ/mol

ΔH°rxn = [3*(-285.83)] - [( -1128.4)] = 270.91 kJ/mol

d) 2Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2Fe(s)

ΔH°f,Fe₂O₃(s) = -824.2 kJ/mol

ΔH°f,Al₂O₃(s) = -1675.7 kJ/mol

ΔH°rxn = [-1675.7] - [-824.2] = -851.5 kJ/mol

3 0
3 years ago
How do particles in a solid move?
satela [25.4K]

Answer:

The particles in a solid vibrate in place.

Explanation:

The particles in a solid are close and tightly packed together so they have no room to flow past each other like the particles in a liquid can.

Hope this helps!

8 0
3 years ago
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