All categories

3 years ago

This answer please :)

Chemistry

1 answer:

Artemon [7]3 years ago

5 0

Answer:

ithink it is c but i dont my ghess

Explanation:

i want to do thos for the points tbh

You might be interested in

It takes a bus driver 30 minutes to pick up students from four stops. The last stop is at the corner of Green Street and Route 7

olga_2 [115]

No, the distance from the first stop to the schools and the average speed is required.

6 0

3 years ago

Read 2 more answers

How can you maximize the use of useful materials that you have identified?

Bas_tet [7]

Answer: The question is not complete, here is the complete question...

How can you maximize the use of useful materials that you have identified? empty bottles, fruits peeling,old news paper

The way to maximize the use of materials identified is by identifying the 3 R's of waste management which are Reduce, Recycle and reuse .

Explanation:

For example, when we check through the materialsempty bottles, fruits peeling,old news paper them can be Reduce, Recycle and reuse.

The plastic bottles can be recycled i.e converting the waste plastic materials into another useful materials like fabric, shoes, mats.

Fruits peeling can be reuse as composts for plants. These can be allow to be decompose which serve as plant compost to release nutrients for plants growth.

Old newspapers can be reduced by been sold to junks shop and some cash can be earned from it.

8 0

3 years ago

Ethyl butyrate, ch3ch2ch2co2ch2ch3, is an artificial fruit flavor commonly used in the food industry for such flavors as orange

kakasveta [241]

Answer:

14.15 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow;

Butanoic Acid + Ethanol → Ethyl Butyrate + Water

Molar Mass of Butanoic Acid = 88.11 g.mol⁻¹

Molar Mass of Ethanol = 46.07 g.mol⁻¹

Molar Mass of Ethyl Butyrate = 116.16 g.mol⁻¹

Molar Mass of Water = 18.01 g.mol⁻¹

Step 1: Calculating Theoretical Yield:

According to Equation,

88.11 g (1 mol) Butanoic Acid forms = 116.16 g (1 mol) Ethyl Butyrate

So,

13.58 g Butanoic Acid will form = X g of Ethyl Butyrate

Solving for X,

X = (13.58 g × 116.16 g) ÷ 88.11 g

X = 17.90 g

Theoretical Yield = 17.90 g

Step 2: Calculating Actual Yield:

As,

%age Yield = Actual Yield ÷ Theoretical Yield × 100

Solving for Actual Yield,

Actual Yield = %age Yield × Theoretical Yield ÷ 100

Putting Values,

Actual Yield = 79.1 × 17.90 ÷ 100

Actual Yield = 14.15 g of Ethyl Butyrate

6 0

3 years ago

Say you have a rock composed entirely of potassium-40. After two half-lives of potassium-40, what fraction of the rock is still

Assoli18 [71]

<u>Answer:</u> The fraction of the rock that is still composed of potassium-40 is 0.25

<u>Explanation:</u>

To calculate the fraction of the rock that is still composed of K-40, we use the formula:

$a=\frac{a_o}{2^n}$

where,

a = amount of reactant left after n-half lives

$a_o$ = Initial amount of the reactant

n = number of half lives = 2

Putting values in above equation, we get:

$\frac{a}{a_o}=\frac{1}{2^2}\\\\\frac{a}{a_o}=\frac{1}{4}=0.25$

Hence, the fraction of the rock that is still composed of potassium-40 is 0.25

8 0

3 years ago

A 988ml sample of air is at 852 mm Hg and 34.1 C. What will the temperature of this gas be, in Fahrenheit, at 955 mm Hg and a vo

prohojiy [21]

Answer:

T₂ = 63.78 °F

Explanation:

Given data:

Initial Volume = 988 mL

Initial Pressure = 852 mmHg

Initial temperature = 34.1 °C

Final pressure = 955 mmHg

Final volume = 602 mL

Final temperature = ?

Solution:

(34.1 °C × 9/5) +32 = 93.38 °F

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂T₁/P₁V₁

T₂ = 955 mmHg × 602 mL × 93.38 °F / 852 mmHg× 988mL.

T₂ = 53685095.8 °F /841776

T₂ = 63.78 °F

4 0

3 years ago