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yulyashka [42]
3 years ago
5

Select the arrangement that indicate the ions in terms of increasing ionic radii

Chemistry
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

The last option, option D is correct.

The order of increasing ionic radii of the three ions given is

Na⁺ < F⁻ < Cl⁻

Check Explanation for reasons why.

Explanation:

For elements in the same group of the periodic table, the ionic radii increases as we move down the group. This is because the number of shells increase as we move further down a group in the periodic table and that automatically confers a bigger radii to the element with the more shells.

So, between F⁻ and Cl⁻, we know the fluoride ion has electronic configuration 2, 8 (2 shells) after it gains an electron to its normal electronic configuration to form the ion, but the chloride ion has electronic configuration 2, 8, 8 (3 shells) when it achieves its own stable octet of outermost electrons.

So, it is clear how Cl⁻ ion has a bigger ionic radii than F⁻ and even Na⁺.

Then, to know which ion is bigger between Na⁺ and F⁻, it is known that when cations and anions have the same electronic configuration, the cations usually have the lesser ionic radii.

This is because in a normal, neutral atom, the number of electrons in the atom matches the number of protons. And the force of attraction between the protons and the electrons matches each other as they both have the same charges and are equal in number.

But cations result from the neutral element losing one or more electrons to achieve that stable octet. This makes the number of protons to exceed the number of electrons, hence, the electrons available are more tightly pulled towards the centre of the atom by the protons in the nucleus of the atom. This results in a reduced ionic radii.

Unlike anions that gain electrons to achieve that stable octet and have the electrons exceeding the protons in their ions, causing the pull of the protons on the electrons to be reduced, thereby resulting in a more repelled electrons pushing the ionic radii further than normal thereby increasing it.

Hope this Helps!!!

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Which statement explains why the bonds between non metals tend to be covalent
UNO [17]
Since the choices are missing, I will tell you why non-metals tend to form covalent bonds. You can then link this answer to the best fit choice.

Ionic bond is only formed due to an electrostatic attraction force between ions of opposite charges which cannot happen in case of non-metals whose ions are mostly anions.

On the other hand, a covalent bond is formed due to electrons being shared among different atoms. This conditions is satisfied for the bonds between non-metals
6 0
3 years ago
In which main energy level does the 'd' sublevel first appear? K (first main energy level) L (second main energy level) M (third
RoseWind [281]

Answer:

M (third main energy level)

Explanation:

The third main energy level bears the first appearance of the 'd' sublevel. The principal quantum number(n) depicts the main energy levels in which an orbital is located. It takes values of n=1,2,3,4,5..... and it can be represented by the shells k,l,m,n.......

The subshells in these main orbitals are represented by s,p,d and f. For the K shell, the principal quantum number is m and its sublevel notations are s,p and d. This is where the d-sublevel first appears.

6 0
3 years ago
Determine the molecular formula for the unknown if the molecular mass is 60.0 amu and the empirical formula is ch2o.
mezya [45]

Answer:

The molecular formule for this unknow molecule is C2H4O2

Explanation:

The empirical formula is CH2O  ( or better said CnH2nOn)

This means there are 3 elements in the formula of this molecule

⇒ Carbon (C) with a Molar mass of 12 g/mole

⇒ Hydrogen (H) with a Molar mass of 1 g/mole

⇒ Oxygen (O) with a Molar mass of 16 g/mole

We can also notice that the amount of hydrogen should 2x the amount of carbon ( also 2x the amount of oxygen).

The mass of the empirical formule = 12g/ mole + 2* 1 g/mole + 16 g/mole = 30 g/mole

To know what number is n in CnH2nOn we should divide the molecular mass by the empirical mass:

60 g/mole / 30g/mole = 2

this means n = 2

and this will give a molecular formule of C2H4O2  

We can control this to calculate the molecular mass:

2*12 + 4* 1 + 2*16 = 24 + 4 + 32 = 60 g/mole

The molecular formule for this unknow molecule is C2H4O2

5 0
3 years ago
En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L
love history [14]

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}

<em>Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio</em>

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = <em>17.3 atm</em>

<em />

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

<em>Donde X representa el avance de reacción.</em>

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

<em>Resolviendo para X:</em>

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = <em>15.454atm</em>

P I₂: X =<em> 0.923atm</em>

P Br₂: X = <em>0.923atm</em>

3 0
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