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nikdorinn [45]
3 years ago
7

As an alternative to ear tags and lip tattoos, tetracycline (an antibiotic) is used to mark polar bears. The advantages of using

tetracycline in this fashion are that it leaves a detectable deposit on the bears’ teeth, it can be administered remotely, and using it doesn’t require that the animal be sedated. If 25 mg/kg is an effective dose, how much tetracycline is needed (in grams) to mark a 880 kg polar bear? Round your answer to two significant figures.
Chemistry
1 answer:
Lerok [7]3 years ago
6 0

<u>Answer:</u> The amount of tetracycline needed for 880 kg of polar bear is 22. grams

<u>Explanation:</u>

We are given:

Effective dose of tetracycline needed = 25 mg/kg = 0.025 g/kg    (Conversion factor:  1 g = 1000 mg)

Mass of the polar bear = 880 kg

Applying unitary method:

For 1 kg of mass, the amount of tetracycline needed is 0.025 grams

So, for 880 kg of mass, the amount of tetracycline needed will be = \frac{0.025g}{1kg}\times 880kg=22.g

Hence, the amount of tetracycline needed for 880 kg of polar bear is 22. grams

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Answer:

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The answer is 9.03 × 10²⁴<span> molecules.

</span><span>Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance.
Make the proportion.
</span><span>6.02 × 10²³ molecules per 1 mol
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6.02 × 10²³ molecules : 1 mol = x : 15 mol
x = 6.02 × 10²³ molecules * 15 mol * 1 mol
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x = 9.03 × 10²³⁺¹ molecules
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4 0
3 years ago
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The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
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where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

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