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nikdorinn [45]
3 years ago
7

As an alternative to ear tags and lip tattoos, tetracycline (an antibiotic) is used to mark polar bears. The advantages of using

tetracycline in this fashion are that it leaves a detectable deposit on the bears’ teeth, it can be administered remotely, and using it doesn’t require that the animal be sedated. If 25 mg/kg is an effective dose, how much tetracycline is needed (in grams) to mark a 880 kg polar bear? Round your answer to two significant figures.
Chemistry
1 answer:
Lerok [7]3 years ago
6 0

<u>Answer:</u> The amount of tetracycline needed for 880 kg of polar bear is 22. grams

<u>Explanation:</u>

We are given:

Effective dose of tetracycline needed = 25 mg/kg = 0.025 g/kg    (Conversion factor:  1 g = 1000 mg)

Mass of the polar bear = 880 kg

Applying unitary method:

For 1 kg of mass, the amount of tetracycline needed is 0.025 grams

So, for 880 kg of mass, the amount of tetracycline needed will be = \frac{0.025g}{1kg}\times 880kg=22.g

Hence, the amount of tetracycline needed for 880 kg of polar bear is 22. grams

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What is the molarity of chloride ion in a solution made by dissolving 1.300g of aluminumchloride in a total volume of 500.0mL?
navik [9.2K]

Answer:

0.0582 M

Explanation:

The following data were obtained from the question:

Mass of AlCl3 = 1.3 g

Volume of water = 500 mL

Molarity of chloride ion (Cl¯) =?

Next, we shall determine the number of mole in 1.3 g of AlCl3. This can be obtained as follow:

Mass of AlCl3 = 1.3 g

Molar mass of AlCl3 = 27 + (35.5×3)

= 27 + 106.5

= 133.5 g/mol

Mole of AlCl3 =?

Mole = mass /molar mass

Mole of AlCl3 = 1.3/133.5

Mole of AlCl3 = 0.0097 mole

Next, we shall convert 500 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

500 mL = 500 mL × 1 L / 1000 mL

500 mL = 0.5 L

Thus, 500 mL is equivalent to 0.5 L.

Next, we shall determine the molarity of the AlCl3 solution. This can be obtained as follow:

Mole of AlCl3 = 0.0097 mole

Volume of water = 0.5 L

Molarity of AlCl3 =?

Molarity = mole /Volume

Molarity of AlCl3 = 0.0097 / 0.5

Molarity of AlCl3 = 0.0194 M

Next, we shall write the dissociation equation of AlCl3 in solution. This is illustrated below:

AlCl3 (aq) —> Al³⁺ (aq) + 3Cl¯ (aq)

From the balanced equation above,

1 mole of AlCl3 produced 3 moles of Cl¯.

Finally, we shall determine the molarity of the chloride ion Cl¯ in the solution as follow:

From the balanced equation above,

1 mole of AlCl3 produced 3 moles of Cl¯.

Therefore, 0.0194 M AlCl3 will produce = 0.0194 × 3 = 0.0582 M Cl¯.

Thus, the molarity of the chloride ion, Cl¯ in the solution is 0.0582 M.

8 0
3 years ago
PLEASE HURRY THIS IS TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AURORKA [14]

Answer:

if i remember correctly i beleive its A  1.8 x 10^24

but im not for sure  also i think you forgot the 24

Explanation:

5 0
3 years ago
How many ATOMS are in 5 grams of NaCl?
Bond [772]

Molar mass of sodium chloride is 22.99 g/mol (Na+) + 35.45 g/mol (Cl-) = x g/mol. Then take the mass of sodium chloride sample 5 grams and divide by molar mass to get the number of moles. Take this number and multiply it by Avogadro’s number (6.22*10^23 molecules/mol). You now have the amount of molecules in 5 grams of NaCl.

5 0
3 years ago
Read 2 more answers
In a lab in New York, Thomas and Nikola collected data over several trials. Thomas recorded his measurements as 10.0 A, 11 A, an
Anna11 [10]

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Explanation:

Precision is the ability to reproduce the same set of result from a measurement. The more repeatability a measurement is, the more precise it is.

 From the given pool of data, it is easy to determine which set of data is more precise over the other.

Thomas measurements: 10.0 A, 11 A, and 8 A

 Nikola measurements: 9.0 A, 9.2 A, 8.8 A

Using the range method, it is possible to find the precision in this pool of data.

Method and Solution:

Find the range of the sample:

        Range = highest value - lowest value

 Thomas measurement; Range = (11-8)A = 3.0A

  Nikola measurement; Range = (9.2-8.8)A = 0.4A

Find the mean of the samples:

Mean of Thomas measurement = \frac{10 + 11+ 8}{3} = \frac{29}{3} = 9.7A

Mean of Nikola measurement = \frac{9+ 9.2+ 8.8}{3} = \frac{27}{3} = 9A

Now let us quote the range of value of the mean of each measurement:

   Thomas 9.7±3.0A

    Nikola   9.0± 0.4A

Nikola's reading has a lower range and it is logical to conclude that his reading is more precise.

Learn more:

mean calculation brainly.com/question/12068498

#learnwithBrainly

5 0
3 years ago
What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?
dusya [7]

Answer:

\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

  • C: 12.011 g/mol
  • H: 1.008 g/mol
  • O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Multiply by the given number of grams.

78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}

Flip the fraction and divide.

78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}

\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

\frac {1 \ L }{ 1000 \ mL}

Multiply by 2500 mL.

2500 \ mL* \frac {1 \ L }{ 1000 \ mL}

2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L

3. Calculate Molarity

Finally, divide the moles by the liters.

molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}

molarity = 0.173183241191 \ mol \ C_6H_12O_6/L

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

molarity \approx 0.17 \ mol \ C_6H_12O_6 /L

1 mole per liter is also equal to 1 M.

molarity = 0.17 \ M \ C_6H_12O_6

3 0
3 years ago
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