Why is Cl weaker base

HELP QUICK!!!

madreJ [45]

Answer:

The 150 g Al will reach a higher temperature.

Explanation:

The amount of heat added to a substance (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).

∵ ΔT is inversely proportional to the mass of the substance.

∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).

So, the right choice is: The 150 g Al will reach a higher temperature.

5 0

3 years ago

Chlorine has two natural isotopes, chlorine-35 and chlorine-37.

Alex Ar [27]

Answer:

The relative atomic mass of chlorine depends on the ratio between the abundance of these two naturally-occurring isotopes.

Explanation:

The relative atomic mass of an element is a weighted average of the atomic mass of its naturally-occurring isotopes. The relative abundance of each isotope gives its weight in this weighted average.

For these two naturally-occurring isotopes of chlorine:

The relative atomic mass of $^{35}{\rm Cl}$ is approximately $34.969$ daltons. The relative abundance of this isotope in nature is approximately $0.758$ .
The relative atomic mass $^{37}{\rm Cl}$ is approximately $36.966$ daltons. The relative abundance of this isotope in nature is approximately $0.242$ .

$\begin{array}{|c|c|c|}\cline{1-3} \text{Isotope} & \text{Atomic Mass} & \text{Relative Abundance}\\ \cline{1-3} ^{35}{\rm Cl} & \approx 34.968\; \rm Da} & \approx 0.758 \\ \cline{1-3} ^{37}{\rm Cl} & \approx 36.966\; \rm Da & \approx 0.242 \\ \cline{1-3}\end{array}$ .

$\begin{aligned}&\text{relative atomic mass of Cl} \\ &= \text{atomic mass of $^{35}{\rm Cl}$} \times \text{relative abundance of $^{35}{\rm Cl}$} \\&\quad + \text{atomic mass of $^{37}{\rm Cl}$} \times \text{relative abundance of $^{37}{\rm Cl}$} \\ &\approx 34.968\; \rm Da \times 0.758 + 36.966\; \rm Da \times 0.242 \\ &\approx 35.45\; \rm Da \end{aligned}$ .

The relative abundance of $^{35}{\rm Cl}$ is much higher than that of $^{37}{\rm Cl}$ . Consequently, the relative atomic mass of the element $\rm Cl$ is closer to the atomic mass of $^{35}{\rm Cl}\!$ than that of $^{37}{\rm Cl}\!$ .

7 0

3 years ago

PLEASE ANSWER!!!!!!!! WILL MARK BRAILIEST

Mariana [72]

9.Pubchem
10.Oxygen
11. Selenium fluoride
12. Disilicon Hexabromide
13. sulfur tetrachloride
14.Methane
15.diboron silicide
16. Nitrogen trifluoride

PLEASE GIVE ME BRAINLIEST!

6 0

3 years ago

What is the mass of 22.4L of H2 at stp

bazaltina [42]

Answer:

2.02 g H₂

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Explanation:

Step 1: Define

22.4 L H₂ at STP

Step 2: Identify Conversions

STP - 22.4 L / mol

Molar Mass of H - 1.01 g/mol

Molar Mass of H₂ - 2(1.01) = 2.02 g/mol

Step 3: Convert

$22.4 \ L \ H_2(\frac{1 \ mol \ H_2}{22.4 \ L \ H_2} )(\frac{2.02 \ g \ H_2}{1 \ mol \ H_2} )$ = 2.02 g H₂

5 0

3 years ago

ANSWER 10 ASAP PLEASE!

Crazy boy [7]

Answer:In geology, petrifaction or petrification is the process by which organic material becomes a fossil through the replacement of the original material and the filling of the original pore spaces with minerals. ... The pores of the organisms' tissues are filled when these minerals precipitate out of the water. Two common types of ...

Explanation:

3 0

4 years ago