Answer:
The number of hydrogen atoms is 4.96x10²⁴.
Explanation:
The number of atoms can be found with the following equation:
![n = N*\eta_{H}](https://tex.z-dn.net/?f=%20n%20%3D%20N%2A%5Ceta_%7BH%7D%20)
Where:
N: is the Avogadro's number = 6.022x10²³ atoms/mol
η: is the number of moles of hydrogen
n: is the number of hydrogen atoms
First, we need to find the number of hydrogen moles. The number of moles of CH₄ is:
![\eta_{CH_{4}} = \frac{m}{M}](https://tex.z-dn.net/?f=%20%5Ceta_%7BCH_%7B4%7D%7D%20%3D%20%5Cfrac%7Bm%7D%7BM%7D%20)
Where:
m: is the mass of methane = 33 g
M: is the molar mass of methane = 16.04 g/mol
![\eta_{CH_{4}} = \frac{33 g}{16.04 g/mol} = 2.06 mol](https://tex.z-dn.net/?f=%20%5Ceta_%7BCH_%7B4%7D%7D%20%3D%20%5Cfrac%7B33%20g%7D%7B16.04%20g%2Fmol%7D%20%3D%202.06%20mol%20)
Now, since we have 4 hydrogen atoms in 1 mol of methane, the number of moles of hydrogen is:
![\eta_{H} = 2.06\: mol\: CH_{4}*4 \frac{mol\: H}{mol \: CH_{4}} = 8.24 mol](https://tex.z-dn.net/?f=%20%5Ceta_%7BH%7D%20%3D%202.06%5C%3A%20mol%5C%3A%20CH_%7B4%7D%2A4%20%5Cfrac%7Bmol%5C%3A%20H%7D%7Bmol%20%5C%3A%20CH_%7B4%7D%7D%20%3D%208.24%20mol%20)
Hence, the number of hydrogen atoms is:
![n = N*\eta_{H} = 6.022 \cdot 10^{23} \: atoms/mol*8.24 mol = 4.96 \cdot 10^{24} atoms](https://tex.z-dn.net/?f=n%20%3D%20N%2A%5Ceta_%7BH%7D%20%3D%206.022%20%5Ccdot%2010%5E%7B23%7D%20%5C%3A%20atoms%2Fmol%2A8.24%20mol%20%3D%204.96%20%5Ccdot%2010%5E%7B24%7D%20atoms)
Therefore, the number of hydrogen atoms is 4.96x10²⁴.
I hope it helps you!
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First convert celcius to Kelvin.
20 + 273 = 293K
31 + 273 = 304K
Now we can set up an equation based on the information we have.
V1 = 5
P1 = 365
T1 = 293
V2 = 5
P1 = x
T2 = 304
The equation be: ![\frac{(5)(365)}{293} = \frac{5x}{304}](https://tex.z-dn.net/?f=%5Cfrac%7B%285%29%28365%29%7D%7B293%7D%20%3D%20%5Cfrac%7B5x%7D%7B304%7D)
Now just solve.
1825/293 = 5x/304
Cross multiply.
554800 = 1465x
Divide both sides by 1465
x = 378.7030717 which can then be rounded to 378.7 mmHg
Answer:
98.3 gradius Celsius
Explanation:
This problem is solved using the Ideal Gas Equation
pV = nRT
...
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
The formula unit for Li and O is —————-> Li2O