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vova2212 [387]
3 years ago
15

Please helpp: All things that are acidic will eventually produce ___ in an aqueous solution?​

Chemistry
2 answers:
BARSIC [14]3 years ago
8 0

Answer:

Protons / H+ ions

Explanation:

Elenna [48]3 years ago
6 0
Protons/h+
hoped this help
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Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo
san4es73 [151]

Answer:

                    1.8 moles of O₂

Explanation:

                     The balance chemical equation for said double replacement (photosynthesis) reaction is as follow;

                           6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

According to balance chemical equation,

                 6 moles of O₂ are produced by  =  6 moles of CO₂

So,

                1.8 moles of O₂ will be produced by  =  X moles of O₂

Solving for X,

                     X =  1.8 mol × 6 mol / 6 mol

                     X =  1.8 moles of O₂

Stoichiometric problems in which moles are given and moles or other reactant or product asked are the simplest problems. One should only write the balanced chemical equation and perform above method to find the required moles.

8 0
3 years ago
A 20.0g sample of metal with a specific heat of 5 J/(g°C) raised it's initial temperature to 40.0 when 500J heat was added. What
slavikrds [6]

The initial temperature of the metal = 35 °C

<h3>Further explanation</h3>

Heat can be formulated :

Q = m . c . ΔT

Q = heat, J

c = specific heat, J/g C

ΔT = temperature, °C

m = 20 g

c = 5 J/(g°C)

Q = 500 J

T₁ = 40 C

the initial temperature :

\tt \Delta t(T_2-T_1)=\dfrac{Q}{m.c}\\\\40-T_1=\dfrac{500}{20.5}\\\\40-T_1=5\\\\T_1=35^oC

3 0
2 years ago
What is the product for MgBr2+ Cl2
nikklg [1K]

???...........…..............

5 0
3 years ago
. MOLECULES that have an uneven pattern of electric charge (more positive in one area; more negative
kondaur [170]
They’re said to be
B. Polar
4 0
2 years ago
How much heat in joules is gained when a 34.5 g bar of gold is heated from 26.4°C to 75.3°C ?specific heat of gold on 0.129 J/gr
Sati [7]

Answer:

Q = 217.63J

Explanation:

Data;

Mass = 34.5g

T1 = 26.4°C

T2 = 75.3°C

c = 0.129J/g°C

Energy (Q) = mc(T2 - T1)

Q = 34.5 * 0.129 *(75.3 - 26.4)

Q = 4.4505 * 48.9

Q = 217.629J

Q = 217.63J

The heat gained was 217.63J

7 0
3 years ago
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