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zlopas [31]
3 years ago
6

1. True or False: When two batteries are wired in Series the Volts go up and the Amp Hours stay the same. 2. True or False: When

to batteries are wired in Parallel the Amp Hours go up and the voltage stays the same. 3. True or False: Voltage is the power of the battery 4. True or False: Amp Hours is how long the power will last 5. True or False: Two 12V Batteries wired together in Series will give you 24 volts of power. 6. True or False: Two 12V Batteries wired together in Parallel will give you 24 Volts of power.
Engineering
1 answer:
madam [21]3 years ago
6 0

Answer:

true when two batteries are wired on series the volts go up and the amp hours stay the same

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A. True

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Please answer fast. With full step by step solution.​
lina2011 [118]

Let <em>f(z)</em> = (4<em>z </em>² + 2<em>z</em>) / (2<em>z </em>² - 3<em>z</em> + 1).

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<em>f(z)</em> = 2 + (8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1)

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2<em>z </em>² - 3<em>z</em> + 1 = (2<em>z</em> - 1) (<em>z</em> - 1)

so you can separate the rational part of <em>f(z)</em> into partial fractions. We have

(8<em>z</em> - 2) / (2<em>z </em>² - 3<em>z</em> + 1) = <em>a</em> / (2<em>z</em> - 1) + <em>b</em> / (<em>z</em> - 1)

8<em>z</em> - 2 = <em>a</em> (<em>z</em> - 1) + <em>b</em> (2<em>z</em> - 1)

8<em>z</em> - 2 = (<em>a</em> + 2<em>b</em>) <em>z</em> - (<em>a</em> + <em>b</em>)

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So we have

<em>f(z)</em> = 2 - 4 / (2<em>z</em> - 1) + 6 / (<em>z</em> - 1)

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<em>f(z)</em> = 2 - (2/<em>z</em>) (1 / (1 - 1/(2<em>z</em>))) + (6/<em>z</em>) (1 / (1 - 1/<em>z</em>))

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\displaystyle\frac1{1-z}=\sum_{n=0}^\infty z^n

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\displaystyle\frac1{1-\frac1z}=\sum_{n=0}^\infty z^{-n}

so that by substitution, we can write

\displaystyle f(z) = 2 - \frac2z \sum_{n=0}^\infty (2z)^{-n} + \frac6z \sum_{n=0}^\infty z^{-n}

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