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2 years ago

8

If you touch a downed power line, covered or bare, what's the likely outcome?

2 answers:

olya-2409 [2.1K]2 years ago

5 0

Answer:

you get electrocuted...........

Andre45 [30]2 years ago

4 0

Most likely you will be dead

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The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a?

Zepler [3.9K]

The component of a regenerative vapor power cycle that permits only liquid to pass through to a region of lower pressure is a Valve/trap.

<h3>What is vapor?</h3>

In physics, a substance in the gas phase at a temperature lower than its critical temperature is referred to as a vapor or vapor.
This means that the vapor can be condensed to a liquid by increasing the pressure on it without decreasing the temperature.
An aerosol is distinct from a vapor.
A suspension of minute liquid, solid, or both types of particles in a gas is known as an aerosol.

<h3>Why does vapor form?</h3>

Evaporation or sublimation are two processes that can be used to create it.
Unlike clouds, fog, or mist, which are only suspended drops of liquid water in the atmosphere, watevaporur is a gas and cannot be seen.
In the atmosphere, water vapor frequently exists below the boiling point.

Learn more about vapor here:

brainly.com/question/14578189

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3 0

1 year ago

PLEASE QUICK!!! what phrase describes an ad hominem fallacy?

Igoryamba

Answer:

personal attack

Explanation:

it is personal attack

5 0

2 years ago

Explain mathematically whether the divergence of the curl of a vector field is

svp [43]

Answer:

yes

Explanation:

6 0

2 years ago

When engineers design solutions to problems (bridge a river, support a building, etc.) there are always certain conditions which

zheka24 [161]

Explanation:

what is your main question

6 0

1 year ago

water flows in a horizontal constant-area pipe; the pipe diameter is 75 mm and the average flow speed is 5 m/s. At the pipe inle

Veronika [31]

Answer:

Head loss = 28.03 m

Explanation:

According to Bernoulli's theorem for fluids we have

$\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=Constant$

Applying this between the 2 given points we have

$\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}=\frac{P_{2}}{\gamma _{w}}+\frac{V_{2}^{2}}{2g}+z_{2}+h_{l}$

Here $h_{l}$ is the head loss that occurs

$\therefore h_{l}=\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}-\frac{P_{2}}{\gamma _{w}}-\frac{V_{2}^{2}}{2g}-z_{2}$

Since the pipe is horizantal we have $z_{1}-z_{2}=0$

Applying contunity equation between the 2 sections we get

$A_{1}V_{1}=A_{2}V_{2}\\\\\therefore V_{1}=V_{2}(\because A_{1}=A_{2})$

Since the cross sectional area of the both the sections is same thus the speed

is also same

Using this information in the above equation of head loss we obtain

$h_{l}=\frac{1}{\gamma _{w}}(P_{1}-P_{2})$

Applying values we get

$h_{l}=\frac{1}{9810}\times (275\times 10^{3})m\\\\\therefore h_{l}=28.03m$

3 0

3 years ago