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lora16 [44]
3 years ago
15

9. An embankment having a volume of 320,000 yd is to be constructed from local borrow. The dry unit weight and moisture content

of the borrow material were determined to be 106 pcf and 18.2%, respectively. The embankment material has a total unit weight of 122 pcf and a moisture content of 16.7%. The volume of borrow lyd needed to construct the embankment is most nearly: (A) 274,100 (B) 315,500 (C) 324,500 (D) 373,600
Engineering
1 answer:
tatuchka [14]3 years ago
3 0

Answer:

correct option is (B) 315,500

Explanation:

given data

volume = 320,000 yd³ = 8640000 ft³

dry unit weight = 106 pcf

moisture content = 18.2%

total unit weight = 122 pcf

moisture content = 16.7%

to find out

volume of borrow lyd needed

solution

first we get here weight of material that is

weight = volume × unit weight

weight = 8640000 ×  122

weight = 1054080000 lb

that weight is weight of water + weight of solid so

0.167 × weight is weight of water + weight of solid ) = 1054080000 lb

and weight of solid = \frac{1054080000}{1.167}

weight of soil solid is = 903239075 pound

and weight of water = 150840925 pound

so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³

and volume required =  8521123.34 ft³ ÷ 27 ft³ =  315597.161 yd³

volume required = 315500 yd³

so correct option is (B) 315,500

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Answer:

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The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (425 + 273.15) K = 698.15 K  

T = 698.15 K

Applying the values as:

2.3\times 10^{13}=6.023\times 10^{24}\times e^{-\frac {Q_v}{1.38\times 10^{-23}\times 698.15}

ln[\frac {2.3}{6.023}\times 10^{-11}]=-\frac {Q_v}{1.38\times 10^{-23}\times 698.15}

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4 0
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Answer:

6:00 pm the next day

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