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lora16 [44]
3 years ago
15

9. An embankment having a volume of 320,000 yd is to be constructed from local borrow. The dry unit weight and moisture content

of the borrow material were determined to be 106 pcf and 18.2%, respectively. The embankment material has a total unit weight of 122 pcf and a moisture content of 16.7%. The volume of borrow lyd needed to construct the embankment is most nearly: (A) 274,100 (B) 315,500 (C) 324,500 (D) 373,600
Engineering
1 answer:
tatuchka [14]3 years ago
3 0

Answer:

correct option is (B) 315,500

Explanation:

given data

volume = 320,000 yd³ = 8640000 ft³

dry unit weight = 106 pcf

moisture content = 18.2%

total unit weight = 122 pcf

moisture content = 16.7%

to find out

volume of borrow lyd needed

solution

first we get here weight of material that is

weight = volume × unit weight

weight = 8640000 ×  122

weight = 1054080000 lb

that weight is weight of water + weight of solid so

0.167 × weight is weight of water + weight of solid ) = 1054080000 lb

and weight of solid = \frac{1054080000}{1.167}

weight of soil solid is = 903239075 pound

and weight of water = 150840925 pound

so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³

and volume required =  8521123.34 ft³ ÷ 27 ft³ =  315597.161 yd³

volume required = 315500 yd³

so correct option is (B) 315,500

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otez555 [7]

Answer:

The work transfer per unit mass is approximately 149.89 kJ

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Explanation:

The given information are;

P₁ = 1 atm

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Therefore, we have for adiabatic system under compression

T_{2} = T_{1}\cdot \left (\dfrac{P_{2}}{P_{1}}  \right )^{\dfrac{\gamma -1}{\gamma }}

Therefore, we have;

T_{2} = 294.2611 \times \left (\dfrac{5}{1}  \right )^{\dfrac{1.5 -1}{1.5 }} \approx 503.179 \ K

The p·dV work is given as follows;

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