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bezimeni [28]
3 years ago
11

Explain why the moon looks different almost every night?

Physics
2 answers:
timofeeve [1]3 years ago
5 0

Because of the different cycles there are of the moon

There are 8 different phases of the moon

lisabon 2012 [21]3 years ago
4 0

Because there are 8 phases the moons have.

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A ball has a mass of 10 Kg. Calculate the force of weight on the ball
LuckyWell [14K]

Answer:

98 N

Explanation:

Weight is mass times acceleration due to gravity.  Assuming the ball is near the surface of the earth, g = 9.8 m/s².

W = mg

W = (10 kg) (9.8 m/s²)

W = 98 N

7 0
3 years ago
A 2.25-kg block is released from rest on a ramp of height h. when the block is released, it slides without friction to the botto
sattari [20]
You need to know shape weit gravity pull and density then will you only know its ms
3 0
4 years ago
The speed of a sound wave in air is 343m/s. If the density of the air is 1.2kg/m3, find the bulk modulus.
Nikolay [14]

Answer:

141178.8

Explanation:

use : density x velocity²

1.2 x 343² = 141178.8 pa

4 0
4 years ago
If a body of mass 5og moves in a circular path of radius 10cm .find work done
Sindrei [870]

Answer:

0Nm, no work is done.

Explanation:

Work done is defined as the Force per distance meaning force times the distance moved in the direction of the force.

Now the body of mass 50g has a centripetal force acting on it directed towards the centre. Now in actuality the body stays along the circle it doesn't really move to the centre of the circle.

Hence the force doesn't move a distance, and so from the definition of work done;

F×d ; d =0

Hence work done = mv2/r × 0= 0Nm

3 0
4 years ago
is placed in the freezer compartment of a refrigerator with a coefficient of performance of 6.00. How much heat energy is exhaus
OLEGan [10]

Answer:

Th heat energy that is exhausted into the room as the water is changed to ice at -5.00 ∘C is H=499.2 kJ.

Explanation:

Incomplete question.

<em>1 L of water at 20.0 is placed in the freezer compartment of a refrigerator with a coefficient of performance of 6.00. How much heat energy is exhausted into the room as the water is changed to ice at -5.00 ∘C?</em>

<em />

We first can calculate the total amount of heat that has to be taken from the mass of water. We can divide this as 3 process:

1) Cooling the water from 20 °C to 0 °C

2) Solidification (enthalpy of solidification)

3) Cooling the ice from 0 °C to -5 °C

1) We can calculate the heat as:

h=c_w\Delta T=4.19\cdot (20-0)=83.8\,kJ/kg

c_w: specific heat of water

2)  We can look up for the latent heat of solifification (or enthalpy of fusion) of water: 333.6 kJ/kg

3) We can calculate the heat as:

h=c_i\Delta T=2.108\cdot (0-(-5))=10.5\,kJ/kg

c_w: specific heat of ice

If we sum the heat extracted in every process, we have:

H=1\,kg\cdot (83.8\,kJ/kg+333.6\,kJ/kg+10.5\,kJ/kg)=427.9\,kJ

The coefficient of performance can be written as:

COP=Q/W=6

This can be interpreted as the freezer consumes 1 kW for every 6 kW it extract from the compartment (and exhaust to the room).

Then, the heat that is exhausted to the room is equal to the heat extracted from the water and the energy consumed by the refrigeration cycle to operate (work W).

We can write this as:

H_r=Q+W=Q+Q/COP=427.9+427.9/6=427.9+71.3=499.2\,kJ

4 0
4 years ago
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