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labwork [276]
3 years ago
5

Due to human demand because of its importance to life, the Earth's most precious resource is 

Physics
2 answers:
pychu [463]3 years ago
3 0
The answer is variant C because every living organism needs water to survive. A human can live without water only 6 days, after that period the most important organs start to shut down because of the lack of water.
Kaylis [27]3 years ago
3 0

Due to human demand because of its importance to life, the Earth's most precious resource is? The answer is C. Freshwater because are most important organs start to shut down after 6 days of no water. The answer is not D. Oil

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Many of the whales in the ocean rely upon tiny marine organisms, called plankton, for food. If all of the plankton suddenly died
exis [7]

Answer:

I believe the answer to be B.

Explanation:

Without food, the whales would die.

8 0
3 years ago
How far does a car travel in 10 s if its initial velocity is 3 m/s and its acceleration
victus00 [196]

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4 0
2 years ago
A cd player uses a ___ to convert info to an electrical signal
Alex_Xolod [135]
C.) Laser. the light from the laser reflects off the shiny surface as the CD rotates
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3 years ago
In 1993 Ileana Salvador of Italy walked 3.0km in under 12min. Suppose that during her walk Salvador is observed to steadily incr
padilas [110]

The distance covered is 115 m

Explanation:

The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance covered

u is the initiaal velocity

v is the final velocity

t is the time elapsed

In this problem, we have:

u = 4.20 m/s

v = 5.00 m/s

t = 25.0 s

Therefore, we can re-arrange the equation to find the distance covered:

s=(\frac{4.20+5.00}{2})(25.0)=115 m

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5 0
3 years ago
SCALCET8 3.9.018.MI. A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the
Firlakuza [10]

Answer:

The length of his shadow is decreasing at a rate of 1.13 m/s

Explanation:

The ray of light hitting the ground forms a right angled triangle of height H, which is the height of the building and width, D which is the distance of the tip of the shadow from the building.

Also, the height of the man, h which is parallel to H forms a right-angled triangle of width, L which is the length of the shadow.

By similar triangles,

H/D = h/L

L = hD/H

Also, when the man is 4 m from the building, the length of his shadow is L = D - 4

So, D - 4 = hD/H

H(D - 4) = hD

H = hD/(D - 4)

Since h = 2 m and D = 12 m,

H = 2 m × 12 m/(12 m - 4 m)

H = 24 m²/8 m

H = 3 m

Since L = hD/H

and h and H are constant, differentiating L with respect to time, we have

dL/dt = d(hD/H)/dt

dL/dt = h(dD/dt)/H

Now dD/dt = velocity(speed) of man = -1.7 m/s ( negative since he is moving towards the building in the negative x - direction)

Since h = 2 m and H = 3 m,

dL/dt = h(dD/dt)/H

dL/dt = 2 m(-1.7 m/s)/3 m

dL/dt = -3.4/3 m/s

dL/dt = -1.13 m/s

So, the length of his shadow is decreasing at a rate of 1.13 m/s

5 0
3 years ago
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