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jek_recluse [69]
3 years ago
6

20pts Physics wave. Plz answer with explanation there are total 4 question

Physics
1 answer:
diamong [38]3 years ago
8 0

Answer:

where are the questions?

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The unit of measurement "mL" describes what property of a substance?
pychu [463]
<span>D. density is your answer</span>
8 0
3 years ago
Read 2 more answers
An interstellar space probe is launched from Earth. After a brief period of acceleration it moves with a constant velocity, 70.0
sleet_krkn [62]

Answer:

22.26 years

, 15.585 light years  , 11.13 light years

Explanation:

a)

t' = t/(\sqrt{1-(v/(c*v)/c)}

= 15.9/\sqrt{(1-0.7*0.7)}

= 22.26 years

b)

0.7*c*22.26 years

=15.585 light years  

c)

0.7*c*15.9

=11.13 light years

3 0
3 years ago
A 6.0 g marble is fired vertically upward using a spring gun. The spring must be compressed 9.4 cm if the marble is to just reac
RoseWind [281]

Answer:

a) \Delta U_{g} = 12.945\,J, b) \Delta U_{k} = 12.945\,J, c) k = 2930.059\,\frac{N}{m}

Explanation:

a) The change in the gravitational potential energy of the marble-Earth system is:

\Delta U_{g} = (0.06\,kg)\cdot \left(9.807\,\frac{m}{s^{2}}\right)\cdot (22\,m)

\Delta U_{g} = 12.945\,J

b) The change in the elastic potential energy of the spring is equal to the change in the gravitational potential energy, then:

\Delta U_{k} = 12.945\,J

c) The spring constant of the gun is:

\Delta U_{k} = \frac{1}{2} \cdot k \cdot x^{2}

k = \frac{2\cdot \Delta U_{k}}{x^{2}}

k = \frac{2\cdot (12.945\,J)}{(0.094\,m)^{2}}

k = 2930.059\,\frac{N}{m}

4 0
3 years ago
Suppose the polar bear was running on land instead of swimming. If the polar bear runs at a speed of about 8.3 m/s, how far will
olga_2 [115]

Answer:

298800 m

Explanation:

v =  \frac{d}{t}

V=speed

d=distance

t=time

d = vt

Change hours to seconds

It will be 36000s

8.3m/s * 36000s

=298800m

8 0
3 years ago
You have a double slit experiment, with the distance between the two slits to be 0.025 cm. A screern is 120 cm behind the double
dimulka [17.4K]

Answer:

The wavelength of the light is 633 nm.

Explanation:

Given that,

Distance between the two slits d= 0.025 cm

Distance between the screen and slits D = 120 cm

Distance between the slits y= 1.52 cm

We need to calculate the angle

Using formula of double slit

\tan\theta=\dfrac{y}{D}

Where, y = Distance between the slits

D = Distance between the screen and slits

Put the value into the formula

\tan\theta=\dfrac{1.52}{120}

\theta=\tan^{-1}\dfrac{1.52}{120}

\theta=0.725

We need to calculate the wavelength

Using formula of wavelength

d\sin\theta=n\lambda

Put the value into the formula

0.025\times\sin0.725=5\times\lambda

\lambda=\dfrac{0.025\times10^{-2}\times\sin0.725}{5}

\lambda=6.326\times10^{-7}\ m

\lambda=633\ nm

Hence, The wavelength of the light is 633 nm.

4 0
3 years ago
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