1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phantasy [73]
2 years ago
13

One of the most effective ways to evaluate data is to try to replicate it.

Physics
2 answers:
WINSTONCH [101]2 years ago
6 0
It seems that you have missed the given options for the given statement above whether it is true or false. But anyway, the correct answer would be TRUE. It is true that one <span>of the most effective ways to evaluate data is to try to replicate it. Hope that this answer will help you. </span>
Dominik [7]2 years ago
3 0

Answer:

The correct answer will be-true

Explanation:

The evaluation of any data relies on two key components: the reproducibility and the replicability of the data which help understand the phenomenon.

The replicability of the data increases the chances of the data as it provides the sample size which can support the existing data also reduces the error along with improving the efficiency and accuracy of the experiment.

Therefore replication of the data is important to any scientific process and thus, true is the correct answer.

You might be interested in
A 0.125 kg hockey puck moving at 20.0 m/s is caught and held by an 85.0 kg goalkeeper at rest. After catching the puck, with wha
jenyasd209 [6]

Answer:

a

Explanation:cuz i saiad so

4 0
3 years ago
These spectra are from the same element. Which is an emission spectrum, which an absorption spectrum?
RSB [31]

Answer:

D. Top is emission; bottom absorption.

Explanation:

Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."

From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.

3 0
3 years ago
Blank is overlapping food chains to better show the way energy moves through an ecosystem​
Komok [63]

A <u>Food web</u> is multiple overlapping food chains.

8 0
3 years ago
A body initially at 100°C cools to 60°C in minutes and to 40°C. The temperature of body at the end of 15 minutes will be​
zhuklara [117]

The question is incomplete, the complete question is;

A body initially at a all 100 degree centigarde cools to 60 degree centigarde in 5 minutes and to 40 degree centigarde in 10 minutes . What is the temperature of surrounding? What will be the temperature in 15 minutes?

Answer:

See explanation

Explanation:

From Newton's law of cooling;

θ1 - θ2/t = K(θ1 + θ2/2 - θo]

Where;

θ1 and θ2 are initial and final temperatures

θo is the temperature of the surroundings

K is the constant

t is the time taken

Hence;

100 - 60/5 = K(100 + 60/2 - θo)

100 - 40/10 = K(100 + 40/2 - θo)

8= (80 - θo)K -----(1)

6= (70 - θo)K -----(2)

Diving (1) by (2)

8/6 = (80 - θo)/(70 - θo)

8(70 - θo) = 6(80 - θo)

560 - 8θo = 480 - θo

560 - 480 = -θo + 8θo

80 = 7θo

θo = 11.4°

Again from Newton's law of cooling;

θ = θo + Ce^-kt

Where;

t= 0, θ = 60° and θo = 11.4°

60 = 11.4 + C e^-K(0)

60 - 11.4 = C

C= 48.6°

To obtain K

40 = 11.4 + 48.6e^-10k

40 -11.4 = 48.6e^-10k

28.6/48.6 = e^-10k

0.5585 = e^-10k

-10k = ln0.5585

k= ln0.5585/-10

K= 0.0583

Hence, the temperature in 15 minutes;

θ= 11.4 + 48.6e^(-0.0583 × 15)

θ= 31.7°

4 0
2 years ago
One day you are driving your friends around town and you drive quickly around a corner without slowing down. You are going at a
Novay_Z [31]

Answer:

1.60 g

Explanation:

From the attached file below:

we can deduce that:

v =  v_x =v_y = 20 \ m/s \\t = 2s

The distance traveled by 2 s will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The length is quarter of the circle  with radius r,

so; if 2 πr = 4 x

Then radius (r) will be:

r = \frac{4x}{2 \pi}\\\\r = \frac{4*40}{2 \pi}

r = 25.5 m

The centripetal acceleration can be expressed as:

a = \frac{v^2}{r}

so;

a = \frac{(20 \ m/s^2)}{25.5 \ m}

a = 15.7 m/s²

the magnitude of the acceleration experienced by your unfortunate passengers in terms of acceleration due to gravity is then determined by the equation:

a' = \frac{a}{g} g

a' = \frac{15.7 \m/s ^2}{9.81 \ m/s^2}\ g

a' = 1.60 \ g

∴ The magnitude of the acceleration experienced by your unfortunate passengers during the turn = 1.60 g

6 0
3 years ago
Read 2 more answers
Other questions:
  • An object of 6 cm height is 16 cm in front of a converging lens with focal length of magnitude 4 cm. What is the dimension of th
    8·1 answer
  • A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 14.0 N.
    5·1 answer
  • What is the definition for Astrology?
    15·1 answer
  • A skydiver is falling at constant velocity. If a force of 600 N is pulling down on the skydiver, how much force must be acting u
    13·2 answers
  • the radius of planet is drecresing by 50%without changing its mass . the acceleration due to gravity will be?​
    15·1 answer
  • what is the position of centre of curvature for concave and convex mirror show with the help of diagram if you can​
    5·1 answer
  • 2. How does inherent value differ from instrumental value? *
    12·1 answer
  • the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly​
    15·1 answer
  • What is an inexpensive, portable, and common way to assess body fat in the fitness industry?
    5·1 answer
  • The self-inductance and capacitance of an LC circuit are 0.20 mH and 5.0 pF. What is the angular frequency at which the circuit
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!