The standard form of a parabola is y=ax²+bx+c
use the three given points to find the three unknown constants a, b, and c:
-2=a+b+c............1
-2=4a+2b+c......... 2
-4=9a+3b+c...........3
equation 2 minus equation 1: 3a+b=0..........4
equation 3 minus equation 2: 5a+b=-2.........5
equation 5 minus equation 4: 2a=-2, so a=-1
plug a=-1 in equation 4: -3+b=0, so b=3
Plug a=-1, b=3 in equation 1: -2=-1+3+c, so c=-4
the parabola is y=-x²+3x-4
double check: when x=1, y=-1+3-4=-2
when x=2, y=-4+6-4=-2
when x=3, y=-9+9-4=-4
Yes.
Answer:
-4u+2v = <-6, 34>
Step-by-step explanation:
u = <4, -7) → -4u = <-16, 28>
v = <5, 3> → 2v = <10, 6>
-4u+2v = <-16, 28> + <10, 6> = <-6, 34>
Answer:
201.06
Step-by-step explanation:
3.14 * 8^2= 201.06
(pi * radius ^ squared)
(-5, 0) and (-1, 0) are the solutions of -2(-x - 3)² + 8 = 0
Step-by-step explanation:
- Step 1: Find the solutions of -2(-x - 3)² + 8 = 0.
Solutions are the intersecting points of y = -2(-x - 3)² + 8 and y = 0.
⇒ Solutions are (-5, 0) and (-1, 0)
- Step 2: (-5, 0) and (-1, 0) are solutions of -2(-x - 3)² + 8 = 0
