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nekit [7.7K]
3 years ago
12

What is 2/3-7/12 need help plzzz

Mathematics
1 answer:
user100 [1]3 years ago
6 0

(2/3) - (7/12)
= .0834 
or in fraction form: 1/12
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I HAVE 2 MIN PLS HELP
Maksim231197 [3]

Answer:

C (ignore this it asked for 20 characters)

5 0
3 years ago
Given An = 5a(n-1) where a1= 2. What are the first 4 terms
nexus9112 [7]

Answer:

2, 10, 50, 250

Step-by-step explanation:

Using the formula with a₁ = 2 , then

a₂ = 5a₁ = 5 × 2 = 10

a₃ = 5a₂ = 5 × 10 = 50

a₄ = 5a₃ = 5 × 50 = 250

The first 4 terms are 2, 10, 50, 250

8 0
3 years ago
Use the arc length formula to find the length of the curve y = 2 − x2 , 0 ≤ x ≤ 1. Check your answer by noting that the curve is
Lina20 [59]

By using the arc length formula, we will see that the length of the curve is L = 1.48

<h3>How to use the arc length formula?</h3>

Here we have the curve:

y = 2 - x^2   with 0 ≤ x ≤ 1

And we want to find the length of the curve.

The arc length formula for a curve y in the interval [x₁, x₂] is given by:

L  =\int\limits^{x_2}_{x_1} {\sqrt{1 + \frac{dy}{dx}^2} } } \, dx

For our curve, we have:

dy/dx = -2x

And the interval is [0, 1]

Replacing that we get:

L  =\int\limits^{1}_{0} {\sqrt{1 + (-2x)^2} } } \, dx\\\\L  \int\limits^{1}_{0} {\sqrt{1 + 4x^2} } } \, dx\\

This integral is not trivial, using a table you can see that this is equal to:

L = (\frac{Arsinh(2x)}{4}  + \frac{x*\sqrt{4x^2 + 1} }{2})

evaluated from x = 1 to x = 0, when we do that, we will get:

L = \frac{Arsinh(2) + 2*\sqrt{5} }{4}  = 1.48

That is the length of the curve.

If you want to learn more about curve length, you can read:

brainly.com/question/2005046

8 0
2 years ago
8 x 2/5 in simplest form
GalinKa [24]

Answer:

3 1/5

Step-by-step explanation:

8/1 = 8

8/1 * 2/5 = 16/5

16/5 = 3 1/5

3 0
2 years ago
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How do I work out 5(a-5)=70 ?
Mama L [17]

Answer:

5a-25=70

5a=70+25

a=95/5

a=19

Step-by-step explanation:

since  a(b+c) = ab+ac

5 0
3 years ago
Read 2 more answers
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