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svet-max [94.6K]
3 years ago
10

When Cullen cleaned behind his dresser, he found 73 cents, all in nickels and pennies. There were 25 coins. How many were nickel

s?
Mathematics
1 answer:
Georgia [21]3 years ago
5 0
Let n = number of nickels, and p = number of pennies.
The number of coins is 25, so we get this equation.
n + p = 25

The value of the coins is 0.05 per nickel, and 0.01 per penny.
0.05n + 0.01p = 0.73

Now you have a system of equations.

n + p = 25
0.05n + 0.01p = 0.73

Solve the first equation for n:
n = 25 - p

Now substitute into the second equation.

0.05(25 - p) + 0.01p = 0.73

1.25 - 0.05p + 0.01p = 0.73

-0.04p = -0.52

p = 13

There were 13 pennies.
Now we substitute 13 for p in n + p = 25 to find out the number of nickels.

n + 13 = 25
n = 12

There are 13 pennies and 12 nickels.

Check: 13 pennies and 12 nickels does total 25 coins.
13 * 0.01 + 12 * 0.05 = 0.13 + 0.60 = 0.73
The value is $0.73.
Our answer is correct.
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. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
3 years ago
Please Help me!!!!!! Its my last question!
Strike441 [17]
The reasonable answer is D makes since
3 0
3 years ago
2r/5+7r/15= rewrite the expression by collecting like terms
kramer
<span>2r/5+7r/15=
LCM=15
(15\5=3*2r=6r)
15\15=1*7r=7r
answer=6r+7r\15
answer=13r\15</span>
3 0
3 years ago
Read 2 more answers
Generic sugar which costs $2.23/kg is made by combining brand X sugar which costs $1.18/kg with brand Y sugar which costs $3.98/
White raven [17]

Answer:

X = 14 kg

Y= 7 kg

Step-by-step explanation:

LET  X and Y equal the amounts of brand X and Y

X = kg of brand X

Y = kg of brand Y

we know:

1)   X    +    Y   =   21    (kg)

2)   1X  +   4Y  =   2(X + Y)        (This is the cost/kg * amounts for total cost)  

Coefficients 1,4,2  are the cost/kg)

substitute eq. 1 (X+Y), = 21 into right side of equation 2

1X + 4Y = (21)*2

use elimination to solve 2 equations

X   +   Y = 21

X   + 4Y = 42        (now subtract,       note:  I wrote the 1X as just X)

------------------

0     -3Y  = -21       OR   Y = 7 kg   so X = (21-7) OR   X = 14 kg

5 0
3 years ago
Please help me! Thanks in advance...
adell [148]
Density of water won't change.

and u should not keep it on the table as it cant support its weight which is

w= density*volume = 62*(3*3*3) =1674 lb which is way greater than 200 lb
3 0
3 years ago
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