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2 years ago

Which solution method would be most efficient to solve the equation (x+3)^2-4=0?

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

6 0

A-Taking The Square Root

B-Factoring

C-Quadratic Formula

You might be interested in

How much is f(10) if f=x^2-2

dangina [55]

To find this value, simply substitute the number 10 in for x in your equation:

$f(x) = x^2 - 2$

$f(10) = 10^2 - 2 = \boxed{98}$

The answer is 98.

8 0

3 years ago

Find the volume of a right circular cone that has a height of 11.4 in and a base with a radius of 5.1 in. Round your answer to t

ella [17]

Answer:

Step-by-step explanation:

h=11.4 in

r=5.1 in

v=3.14*r^2*(h/3)

V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35

5 0

2 years ago

Please explain me how to solve it <br> cos2x+cos4x ≥0

Sliva [168]

2x + 4x will always be larger or equal to 0.
if x= 0 than it will be equal to 0.
Does this help at all?

3 0

3 years ago

A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis

VMariaS [17]

Answer:

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=320128$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=50324$ represent the population standard deviation

n=529 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$