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tekilochka [14]
3 years ago
11

Segment J K has coordinates J begin ordered pair 3 comma negative 6 end ordered pair and K begin ordered pair negative 3 comma 2

end ordered pair.
When segment J K is dilated with a scale factor negative 4, what are the coordinates of J prime and K prime?

options:

J prime begin ordered pair negative 12 comma 24 end ordered pair and K prime begin ordered pair 12 comma negative 8 end ordered pair

J primebegin ordered pair negative 1 comma negative 10 end ordered pair and K prime begin ordered pair negative 7 comma negative 2 end ordered pair

J prime begin ordered pair negative fraction 3 over 4 end fraction comma 3 over 2 end ordered pair and K prime begin ordered pair 3 over 4 comma negative 1 half end ordered pair

J prime begin ordered pair 7 comma negative 2 end ordered pair and K prime begin ordered pair 1 comma 6 end ordered pair
Mathematics
1 answer:
mario62 [17]3 years ago
8 0
J' is at (-12, 24) and K' is at (12, -8).

Multiply both the x- and y-coordinates of J by -4; then do the same with the coordinates of K.
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3 0
3 years ago
Over the summer, Mr. Patel refilled a bird feeder 24 times using 6 cups of seed each time. A bag of seeds holds 32 cups. How man
Illusion [34]

Mr. Patel used 4.5 bags of seed

<em><u>Solution:</u></em>

Given that,

Over the summer, Mr. Patel refilled a bird feeder 24 times using 6 cups of seed each time

A bag of seeds holds 32 cups

1 bag of seed = 32 cups

Given that Patel refilled 24 times using 6 cups of seed each time

<em><u>Then, the number of cups used for the 24 times  is given as:</u></em>

6 \times 24 = 144

<em><u>Now we have to find the bags of seed needed for 144 cups</u></em>

Let "x" be the number of bags of seed for 144 cups

From given,

1 bag of seed = 32 cups

"x" bags of seed = 144 cups

This forms a proportion and we can solve it by cross multiplying

144 \times 1 = 32 \times x\\\\144 = 32x\\\\x = \frac{144}{32}\\\\x = 4.5

Thus 4.5 bags of seed is used by Mr.patel

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4 years ago
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