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3 years ago

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Chemistry

2 answers:

Allisa [31]3 years ago

8 0

Answer:

the ansr is c

Explanation:

arsen [322]3 years ago

5 0

Answer:

its b

Explanation:

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_KOH + _H₂PO4 → _K₂PO4 + _H₂O

Hunter-Best [27]

Answer:

2KOH+H2PO4--K2PO4+4H2O

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3 years ago

The mechanical advantage of a door knob that allows you to move a boli

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Answer:

the mechanical advantage is 50 because 0.50/0.01=50

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4 years ago

g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord

Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

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3 years ago

The distance from the trough of one wave to the trough of another wave is wave amplitude

Alexxandr [17]

This is actually incorrect, the distance as stated above either from trough to trough or from crest to crest within a corresponding wave, would be referred or called as the wavelength of the given wave.

6 0

4 years ago

Read 2 more answers

Data has been collected to show that at a given wavelength in a 1 cm pathlength cell, Beer's Law for the absorbance of Co2 is li

White raven [17]

Answer : The concentration of a solution with an absorbance of 0.420 is, 0.162 M

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

As per question, at constant path-length there is a direct relation between absorbance and concentration.

$\frac{A_1}{A_2}=\frac{C_1}{C_2}$

where,

A = absorbance of solution

C = concentration of solution

l = path length

$A_1$ = initial absorbance = 0.350

$A_2$ = final absorbance = 0.420

$C_1$ = initial concentration = 0.135 M

$C_2$ = final concentration = ?

Now put all the given value in the above relation, we get:

$\frac{0.350}{0.420}=\frac{0.135}{C_2}$

$C_2=0.162M$

Thus, the concentration of a solution with an absorbance of 0.420 is, 0.162 M

4 0

3 years ago