Ask question

Ask question

All categories

3 years ago

8

How does a pin hole camera work? And how do we see through them?

2 answers:

DIA [1.3K]3 years ago

6 0

A pinhole camera<span> is a simple </span>camera<span> without a lens but with a tiny aperture, a</span>pinhole<span> – effectively a light-proof box with a small hole in one side. Light from a scene passes through the aperture and projects an inverted image on the opposite side of the box, which is known as the </span>camera<span> obscura effect.</span>

maxonik [38]3 years ago

3 0

A pinhole camera<span> is a simple </span>camera<span> without a lens but with a tiny aperture, a </span>pinhole<span> – effectively a light-proof box with a small hole in one side. Light from a scene passes through the aperture and projects an inverted image on the opposite side of the box, which is known as the </span>camera<span> obscura effect.

Hope this helps! ^-^</span>

You might be interested in

My Exams are coming.so, please tell me some ways to score good marks?

Citrus2011 [14]

Instead of asking this question go and study

5 0

2 years ago

Read 2 more answers

What is the voltage across a semiconductor bar if the current through it is 0.17 A? The electron concentration in the bar is 2.7

Anastaziya [24]

Answer:

The voltage across a semiconductor bar is 0.068 V.

Explanation:

Given that,

Current = 0.17 A

Electron concentration $n= 2.7\times10^{18}\ cm^{-3}$

Electron mobility $\mu=1000 cm^2/Vs$

Length = 0.1 mm

Area = 500 μm²

We need to calculate the resistivity

Using formula of resistivity

$\sigma=n\times q\times \mu$

$\rho=\dfrac{1}{\sigma}$

Put the value into the formula

$\rho=\dfrac{1}{2.7\times10^{18}\times10^{6}\times1.6\times10^{-19}\times1000\times10^{-4}}$

$\rho=2\ \mu \Omega m$

We need to calculate the resistance

Using formula of resistance

$R=\dfrac{\rho l}{A}$

$R=\dfrac{2\times10^{-6}\times0.1\times10^{-3}}{500\times(10^{-6})^2}$

$R=0.4\ \Omega$

We need to calculate the voltage

Using formula of voltage

$V= IR$

Put the value into the formula

$V=0.17\times0.4$

$V=0.068\ V$

Hence, The voltage across a semiconductor bar is 0.068 V.

6 0

3 years ago

alexgriva [62]

Answer:

Get your answer for $1 from www.gotit-pro.com

Explanation:

6 0

3 years ago

A fully loaded cart with a mass of 2200 kg starts from the top of a 12-meter hill on a roller coaster.

Salsk061 [2.6K]

Answer:

A. potential energy is 258720 Joule

Explanation:

A.Gravitational potential energy is: PE = m × g × h

velocity = 15.33 m/s when the car reaches the bottom of the hill.

where, m = mass

g = acceleration due to gravity

h = height from the bottom of hill.

The potential energy is : m×g×h

=(2200×9.8×12)

=258720 Joule

B. at the bottom of the hill, the potential energy is converted into kinetic energy so PE at top = KE at bottom

kinetic energy= $\frac{1}{2}$ ( $m*v^{2}$ )

where v = velocity

m= mass

therefore, v= $\sqrt\frac{2*K.E}{m} {}$

or, v= $\sqrt{\frac{2*258720}{2200} }$

or, v=15.33 m/s

7 0

3 years ago

Plants appear green because they do not absorb the green wavelengths of light what happens to those green light waves when they

Arlecino [84]

The green wavelengths are reflected, causing green to be the only color we see in certain parts of plants.

Best of luck, my man.

4 0

3 years ago

Read 2 more answers