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kobusy [5.1K]
3 years ago
6

The small intestine _____.

Physics
2 answers:
icang [17]3 years ago
6 0

Answer:

digests food

Explanation:

VladimirAG [237]3 years ago
3 0

Answer:

the small intestine digest food

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Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 3.04 m away from a waterfall 0.585 m in heigh
S_A_V [24]

Answer:

V₀ = 5.47 m/s

Explanation:

The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 3.04 m

θ = Launch Angle = 41.7°

V₀ = Minimum Launch Speed = ?

g = 9.81 m/s²

Therefore,

3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)

V₀² = 3.04 m/(0.10126 s²/m)

V₀ = √30.02 m²/s²

<u>V₀ = 5.47 m/s</u>

6 0
2 years ago
A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration
Mekhanik [1.2K]
The players acceleration is 3.33 m/s/s

Acceleration= Velocity/Time

A =10/3
4 0
3 years ago
Read 2 more answers
How is distance related to force in this experiment to mass
Elden [556K]
When distance<span> is increased the amount of </span>force<span> needed will depend on the </span>mass<span> of the object. </span>
5 0
3 years ago
A rocket has a mass 280(103) slugs on earth. Specify its mass in SI units, and its weight in SI units.
saw5 [17]

To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then

A: Using the conversion ratio of slug to kilogram we have to,

1 slug = 14.59kg

Then

m = 280*10^3 slugs (\frac{14.59kg}{1slug})

m = 4.09*10^6kg

B: Using Newton's second law we have to,

W = mg

W = (4.09*10^6)(9.8)

W = 40034960N\approx 4*10^7N

8 0
3 years ago
Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0
3 years ago
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