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-BARSIC- [3]
3 years ago
13

If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev

ious question. what acceleration would this fully functional jet experience if it were towing 2.4 identical but inopeational jets?
Physics
1 answer:
soldi70 [24.7K]3 years ago
3 0

Answer:

5.22m/s^2

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

X = \frac{2.4 * 100\%} { 4 }= 60\%

In this way it would mean that the body could be driven to 60% of its total.

So

Speed_{Decreased} = 8.7 * 60\% = 5.22 \frac{m}{s^2}

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kotegsom [21]

Answer:

Q = 1057.5 [cal]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

Q=m*C_{p}*(T_{final}-T_{initial})

where:

Q = heat energy [cal]

Cp = specific heat = 0.47 [cal/g*°C]

T_final = final temperature = 32 [°C]

T_initial = initial temperature = 27 [°C]

m = mass of the substance = 450 [g]

Now replacing:

Q=450*0.47*(32-27)\\Q=1057.5[cal]

5 0
3 years ago
Use the Bohr model to address this question. When a hydrogen atom makes a transition from the 5 th energy level to the 2nd, coun
iris [78.8K]

Answer:

A. 2.82 eV

B. 439nm

C. 59.5 angstroms

Explanation:

A. To calculate the energy of the photon emitted you use the following formula:

E_{n1,n2}=-13.4(\frac{1}{n_2^2}-\frac{1}{n_1^2})     (1)

n1: final state = 5

n2: initial state = 2

Where the energy is electron volts. You replace the values of n1 and n2 in the equation (1):

E_{5,2}=-13.6(\frac{1}{5^2}-\frac{1}{2^2})=2.82eV

B. The energy of the emitted photon is given by the following formula:

E=h\frac{c}{\lambda}   (2)

h: Planck's constant = 6.62*10^{-34} kgm^2/s

c: speed of light = 3*10^8 m/s

λ: wavelength of the photon

You first convert the energy from eV to J:

2.82eV*\frac{1J}{6.242*10^{18}eV}=4.517*10^{-19}J

Next, you use the equation (2) and solve for λ:

\lambda=\frac{hc}{E}=\frac{(6.62*10^{-34} kg m^2/s)(3*10^8m/s)}{4.517*10^{-19}J}=4.39*10^{-7}m=439*10^{-9}m=439nm

C. The radius of the orbit is given by:

r_n=n^2a_o   (3)

where ao is the Bohr's radius = 2.380 Angstroms

You use the equation (3) with n=5:

r_5=5^2(2.380)=59.5

hence, the radius of the atom in its 5-th state is 59.5 anstrongs

8 0
3 years ago
The instantaneous velocity of an object is the blank of the object with a blank
miss Akunina [59]
Instantaneous velocity is the velocity at a specific instant in time. I bet you are taking Honors Physics. 
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3 years ago
What is the mechanical advantage of a lever that has an input arm of 6 meters and an output arm of 2 meters
Setler79 [48]

Answer:A

Explanation:I TOOK THE Test

5 0
3 years ago
Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea
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Answer:

v = 3869 m/s

Explanation:

As we know that the orbital speed of the satellite is given as

v = \sqrt{\frac{GM}{r}}

also we know that

time period of the revolution is given as

T = \frac{2\pi r}{v}

now from above equation we know that

T = \frac{2\pi (\frac{GM}{v^2})}{v}

T = \frac{2\pi GM}{v^3}

so we will have

v = (\frac{2\pi GM}{T})^{1/3}

now plug in all data in this equation

v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}

v = 3869 m/s

3 0
3 years ago
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