Answer:
B. The same on the moon.
Explanation:
The density of an object is the ratio of the mass contained by the object to the volume occupied by that mass.
When the object is taken from the earth to anywhere in the universe, its mass remains constant. The dimensions of the object and hence its volume also remains constant anywhere in the universe.
Therefore, the density of the object will also remain the same as it depends upon the mass and the volume of the object.
So, the correct option is:
<u>B. The same on the moon.</u>
Answer:
28.3 m/s
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Maximum height (H) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Initial velocity (u) =?
Thus, we can obtain the minimum velocity cannon ball by using the following formula:
H = u²Sine² θ / 2g
10 = u² × (Sine 30)² / 2× 10
10 = u² × (0.5)² / 20
10 = u² × 0.25 / 20
10 = u² × 0.0125
Divide both side by 0.0125
u² = 10/ 0.0125
u² = 800
Take the square root of both side
u = √800
u = 28.3 m/s
Therefore, the minimum speed of the cannon ball is 28.3 m/s
The first one is B
and the second one is A hope this helps
Answer:
1.8 kj
Explanation:
Explanation:
A substance's specific heat tells you how much heat is required to increase the mass of
1 g
of that substance by
1
∘
C
.
The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- heat absorbed
m
- the mass of the sample
c
- the specific heat of the substance
Δ
T
- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample
You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for
q
q
=
250.0
g
⋅
0.14
J
g
∘
C
⋅
(
62
−
10
)
∘
C
=
1820 J
I'll leave the answer rounded to two sig figs and expressed in kilojoules
q
=
1.8 kJ
Answer Explanation:
A substance's specific heat tells you how much heat is required to increase the mass of
1 g
of that substance by
1
∘
C
.
The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- heat absorbed
m
- the mass of the sample
c
- the specific heat of the substance
Δ
T
- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample
You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for
q
q
=
250.0
g
⋅
0.14
J
g
∘
C
⋅
(
62
−
10
)
∘
C
=
1820 J
I'll leave the answer rounded to two sig figs and expressed in kilojoules
q
=
1.8 kJ
Answer link
Answer:
the acceleration of an object is dependent upon two variables the net force acting upon the object and the mass of the object
