The force exerted on his torso by his legs during the deceleration is 4365 N.
<u>Explanation:</u>
Mass of the torso m=45kg
Height of the building s=3.5 m
Decelerating distance=0.71 m
when he jumps to the ground, the only acceleration is acceleration due to gravity g
<u>motion1 from top to ground </u>
initial velocity u=0
we have to calculate final velocity v using the following equation of motion.

use height of the building as the distance s as the jump from top to the ground is only described here.
<u>Motion 2 on the ground</u>
v=0
u=8.3(final velocity of motion 1)
The deceleration after striking the ground can be calculated from the equation of motion

The decelerating distance is used in the place of s since since the motion after hitting the ground is described in this case.
The equation of force is

Answer:
Crest is the highest point that a wave reaches and… Trough the lowest point that a wave reaches............Transverse waves are waves whose particles vibrate at right angles to the direction of wave travel e.g water wave. .....,.......longitudinal I think it's not "longitudin" are waves whose particles vibrate in a direction parallel to the direction of wave travel e.g sound wave
The mass number (the amount of protons and neutrons that element has altogether)
Answer:
(a) 
Explanation:
We have given speed of light 
Given time = 1 year =365 days
We know that in 1 minute = 60 sec
1 hour = 60×60 = 3600 sec
In one day = 24 hour = 24×60×60=86400 sec
So in 365 days = 365×86400
We know that distance = speed ×time
We have given that 1 mi = 1609 m
So
So option (a) is correct