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3 years ago

Is 11,13,17 a right triangle

Mathematics

2 answers:

aliya0001 [1]3 years ago

6 0

Answer: no

Step-by-step Explanation: If the sum of the squares of two sides of a triangle is equal to the square of the third side or a² + b² = c², then the triangle is <u>right</u>.

In this problem, we're given a triangle that has

sides with lengths of 11, 13, and 17.

Let's plug these lengths into the pythagorean theorem.

(11)² + (13)² = (17)² or 121 + 169 = 289.

Since 121 + 169 ≠ 289, this is not a right triangle.

11Alexandr11 [23.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

We can use the Pythagorean theorem to check

a^2 +b^2 = c^2

11^2+13^2 = 17^2

121+169 =289

410 does not equal 289

This is not a right triangle

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50% of 180 dancers said they prefer hip hop class over tap class. How many dancers prefer hip hop class?

Simora [160]

Answer:

Step-by-step explanation:

50% of 180 = 90%

90% is the answer.

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2 years ago

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on. He continues to double his savings each

zheka24 [161]

ANSWER

$16,384

EXPLANATION

From the question we have that,

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on.

This forms a geometric sequence,

$1,2,4,...$

The first term of this sequence is

$a = 1$

The common ratio is

$r = \frac{2}{1} = \frac{4}{2} = 2$

The general term of a geometric sequence is given by the formula:

$f(n) = a {r}^{n - 1}$

To find the 15th term, we plug in a=1, r=2 and n=15.

$f(15) = 1 {(2)}^{15 - 1}$

$f(15) = {2}^{14}$

$f(15) = 16384$

The amount he will save on the 15th day is $16,384

4 0

3 years ago

A number tripled and tripled again is 576. What is the number?

Oksana_A [137]

Answer:

192

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Anna has 7 baskets and some flowers. she has 5 fewer baskets than flowers. how many flowers does anna have

MrRa [10]

Answer:

2 flowers

Step-by-step explanation:

if she has 7 baskets and 5 fewer baskets than flowers

you get the equation 7-5 which is 2

8 0

3 years ago

According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i

Ierofanga [76]

Answer:

a) $P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

b) $P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

c) For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

And replacing we got:

$P(X\geq 8)=0.0000779$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Bin (n=10 ,p=0.2)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:

$X \sim Binom(n=10, p=0.2)$

Part a

We want to find this probability:

$P(X=2)$

And using the probability mass function we got:

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

Part b

For this case we want this probability:

$P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)$

We can find the individual probabilities and we got:

$P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107$

$P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268$

$P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302$

And replacing we got:

$P(X\leq 2) = 0.107+0.268+0.302=0.678$

Part c

For this case we want this probability:

$P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)$

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

$P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302$

$P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268$

$P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107$

And replacing we got:

$P(X \geq 8) = 0.677$

3 0

3 years ago