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Inga [223]
3 years ago
14

Which best compares the gravitational force and the strong force ?

Physics
2 answers:
Elan Coil [88]3 years ago
8 0
<span>The heavier the body is, the stronger its gravitational pull. Example, the Milky Way Galaxy has a gravitational pull because of the heavenly bodies such as stars and planets are surrounding it. A strong force is exerted if the mass of another body is bigger than the other body.</span>
Natali [406]3 years ago
3 0

Explanation:

Gravitational force :

Gravitation force is an attractive force which act between two bodies.

This force acts between the objects with mass.

The gravitational force is the proportional to the product of their masses of the bodies and inversely proportional to the square of distance between the bodies.

Gravitational force only attraction force.

The gravitational force is very weak force.

Strong force :

The force which holds nucleus together it called strong force.

This force is attractive and repulsive force.

The strong force like electromagnetic force it has short range.

The range of strong force is 10⁻¹⁵ m.

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Changing the speed of a synchronous generator changes A) the frequency and amplitude of the output voltage. B) only the frequenc
Dmitrij [34]

Answer:

A) the frequency and amplitude of the output voltag

Explanation:

Changing the speed of a synchronous generator changes both the output voltage (amplitude of the wave) and frequency as they tend to increase.

Changing the speed regulator will change the engine throttle setting to maintain the speed.

While the power, torque, current, fuel flow rate and torque angle will have decreased.

8 0
3 years ago
An object initially at rest experiences an acceleration of 0.281 m/s2 to the South for a time of 5.44 seconds. It then increases
andre [41]

Answer:

12.0 meters

Explanation:

Given:

v₀ = 0 m/s

a₁ = 0.281 m/s²

t₁ = 5.44 s

a₂ = 1.43 m/s²

t₂ = 2.42 s

Find: x

First, find the velocity reached at the end of the first acceleration.

v = at + v₀

v = (0.281 m/s²) (5.44 s) + 0 m/s

v = 1.53 m/s

Next, find the position reached at the end of the first acceleration.

x = x₀ + v₀ t + ½ at²

x = 0 m + (0 m/s) (5.44 s) + ½ (0.281 m/s²) (5.44 s)²

x = 4.16 m

Finally, find the position reached at the end of the second acceleration.

x = x₀ + v₀ t + ½ at²

x = 4.16 m + (1.53 m/s) (2.42 s) + ½ (1.43 m/s²) (2.42 s)²

x = 12.0 m

5 0
3 years ago
10 points!! If you help!!!
marta [7]

For Mass

K.E = (1/2*mv^2)

Explanation:

Kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

4 0
3 years ago
If a train travels 80 miles north, 60 miles east, what’s the magnitude of its total displacement? Find the solution by drawing a
AnnZ [28]

Answer:

100 miles North East.

Explanation:

Please see attached photo for diagram.

In the attached photo, X represents the magnitude of the total displacement of the train.

Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:

X² = 80² + 60²

X² = 6400 + 3600

X² = 10000

Take the square root of both side

X = √10000

X = 100 miles.

Therefore, the magnitude of the total displacement of the train is 100 miles North East.

8 0
3 years ago
A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no apprecia
Elenna [48]

Answer:A brick is released with no initial speed from the roof of a building and strikes the ground in 2.50 s, encountering no ..

6 0
2 years ago
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