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3 years ago

Which best compares the gravitational force and the strong force ?

2 answers:

8 0

<span>The heavier the body is, the stronger its gravitational pull. Example, the Milky Way Galaxy has a gravitational pull because of the heavenly bodies such as stars and planets are surrounding it. A strong force is exerted if the mass of another body is bigger than the other body.</span>

Natali [406]3 years ago

3 0

Explanation:

Gravitational force :

Gravitation force is an attractive force which act between two bodies.

This force acts between the objects with mass.

The gravitational force is the proportional to the product of their masses of the bodies and inversely proportional to the square of distance between the bodies.

Gravitational force only attraction force.

The gravitational force is very weak force.

Strong force :

The force which holds nucleus together it called strong force.

This force is attractive and repulsive force.

The strong force like electromagnetic force it has short range.

The range of strong force is 10⁻¹⁵ m.

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nikdorinn [45]

Most likely it would be C not completely sure

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3 years ago

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A wheelchair ramp is 5.2 m long and 0.8 m high. Calculate the ramp’s mechanical advantage

Arlecino [84]

Answer:

Explanation:

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3 years ago

A rectangular piece of cardboard, whose area is 352 square centimeters, is made into an open box by cutting a 2-centimeter sq

Usimov [2.4K]

Answer:

Dimension of cardboard is 22 m by 16 m

Explanation:

Given that,

Area = 352 cm²

Side of each square cutting from corner = 2 cm

Volume of box = 432 cm³

Let the two sides are x and y.

The area of the rectangular piece is

$xy=352$

$y=\dfrac{352}{x}$ -------- (1)

The volume of the rectangular piece

$2(x-4)(\dfrac{352}{x}-4)=432$

$x^2-38x+352=0$

$(x-16)(x-22)=0$

x=16,22

Put the value of x in the equation (I)

For x = 16

$y=\dfrac{352}{16}=22$

For x = 22

$y=\dfrac{352}{22}=16$

Dimension of cardboard is 22 m by 16 m

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3 years ago

Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10

nydimaria [60]

Answer:

Explanation:

The formula for this is

$F_g=\frac{Gm_1m_2}{r^2}$ where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.

Filling in:

$7.5*10^{-8}=\frac{6.67*10^{-11}(90.0)(30.0)}{r^2}$ and moving things around to solve for r:

$r=\sqrt{\frac{6.67*10^{-11}(90.0)(30.0)}{7.5*10^{-8}} }$ Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m

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3 years ago

If 2 grams of element X combine with 4 grams of element Y to form compound XY, how many grams of element Y would combine with 46

Butoxors [25]

92 grams of Y would combine with 46 grams of X

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3 years ago