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Digiron [165]
3 years ago
13

What must be the acceleration of a train in order for it to stop from 12m/s in a distance of 541m?

Physics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

-0.133 m/s²

Explanation:

Given:

Δx = 541 m

v₀ = 12 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (12 m/s)² + 2a (541 m)

a = -0.133 m/s²

krok68 [10]3 years ago
5 0

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

<em>P.S. This is part of the answer of another brainly user this is not my knowledge.</em>

<em>But Hope I helped you</em>

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How to solve arctan[tan(7pi /4)] ...?
Svet_ta [14]
Well, 
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pi is a period of tangent function: 
so 
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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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