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grandymaker [24]
3 years ago
9

In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

e generator were only 20% efficient (which is more realistic), how much energy in joules would be converted to electrical energy and how much would be lost to heat? (2 points)​
Chemistry
1 answer:
algol [13]3 years ago
6 0

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

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Choose the substance with the lowest boiling point.
MA_775_DIABLO [31]

Answer:

E. O2

Explanation:

All substances has a simple molecular structure, where between their molecules are held by van der Waals' forces. But C must be incorrect because between the H2O2 molecules, they are mainly held by hydrogen bonds on top of van der Waals' forces. Hydrogen bonds are stronger than van der Waals' forces, so more energy is required to separate the H2O2 molecules.

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8 0
3 years ago
Object A has a mass of 10 g and a volume of 8 cm3. Object B has a mass of 10 g and a volume of 6 cm3. Which object has a greater
sweet [91]
Mass of object A = 10g
volume of object A = 8cm³
Mass of object B = 10g
Volume of Object B = 6cm³
we use the following formula to calculate the density of object A and B.
Density = Mass / Volume
Density of Object A = 10g / 8cm³ = 1.25g/cm³
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So the density of object B is greater than object A
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6 0
3 years ago
Read 2 more answers
COLLEGE CHEMISTRY 35 POINTS
Sati [7]

6.81% is the percent yield when 12 g of CO2 are formed experimentally from the reaction of 0.5 moles of C8H18 reacting with excess oxygen.

Explanation:

Data given:

mass of carbon dioxide formed = 12 grams (actual yield)

atomic mass of CO2 = 44.01 grams/mole

moles of C_{8} H_{18} = 0.5

Balanced chemical reaction:

2 C_{8} H_{18} + 25 O_{2} ⇒ 16 CO_{2} + 18 H_{2} _O{}

number of moles of carbon dioxide given is

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles= \frac{12}{44}

number of moles of carbon dioxide gas = 0.27 moles

from the reaction 2 moles of C_{8} H_{18} reacts to produce 16 moles of CO_{2}

So, when 0.5 moles reacted it produces x moles

\frac{16}{2} = \frac{x}{0.5}

x = 4

4 moles of carbon dioxide formed, mass from it will give theoretical yield.

mass  = number of moles x molar mass

mass = 4 x 44.01

        = 176.04 grams

percent yield =\frac{actual yield}{theoretical yield} x 100

percent yield = \frac{12}{176.04} x 100

     percent yield  = 6.81 %

8 0
3 years ago
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