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grandymaker [24]
2 years ago
9

In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

e generator were only 20% efficient (which is more realistic), how much energy in joules would be converted to electrical energy and how much would be lost to heat? (2 points)​
Chemistry
1 answer:
algol [13]2 years ago
6 0

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

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Yuri [45]

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5 0
2 years ago
Which of the following is the correct formula used for calculating Speed?
MAXImum [283]

Answer:

A- Speed = distance/time

Explanation:

Would make sense and that's what I remember

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3 years ago
Calculate the number of moles of C2H6 (nC2H6) in 1.80×1023 molecules of C2H6.
dem82 [27]
1481.40 molecules of C2H6
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3 years ago
HELP. I DONT KNOW WHAT TO DO. Barium sulfate, BaSO4, is made by the following reaction.
Ghella [55]

Answer:

\boxed{\text{66.95 g BaSO$_{4}$}}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:         261.34                         233.39

              Ba(NO₃)₂ + Na₂SO₄ ⟶ BaSO₄ + 2NaNO₃

m/g:         75.00

1. Moles of Ba(NO₃)₂

\text{Moles of Ba(NO$_{3})_{2}$} = \text{75.00 g} \times \dfrac{\text{1 mol}}{\text{261.34 g}} = \text{0.286 98 mol}

2. Moles of BaSO₄

The molar ratio is (1 mol BaSO₄/1 mol Ba(NO₃)₂

\text{Moles of BaSO$_{4}$}= \text{0.286 98 mol Ba(NO$_{3})_{2}$ } \times \dfrac{\text{1 mol BaSO$_{4}$}}{\text{1 mol Ba(NO$_{3})_{2}$}} = \text{0.286 98 mol BaSO$_{4}$}

3. Mass of BaSO₄

\text{Mass of BaSO$_{4}$} = \text{0.286 98 mol BaSO$_{4}$} \times \dfrac{\text{233.39 g BaSO$_{4}$}}{\text{1 mol BaSO$_{4}$}} = \textbf{66.98 g BaSO$_{4}$}\\\\\text{The theoretical yield of barium sulfate is } \boxed{\textbf{66.98 g BaSO$_{4}$}}

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3 years ago
In the analysis of hair and fiber samples, which does a compound comparison microscope allow for that a conventional compound mi
Alex777 [14]

I believe it would be D. Higher magnification

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