The first dissociation for H2X:
H2X +H2O ↔ HX + H3O
initial 0.15 0 0
change -X +X +X
at equlibrium 0.15-X X X
because Ka1 is small we can assume neglect x in H2X concentration
Ka1 = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15)
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
HX + H2O↔ X^2 + H3O
8.2x10^-4 Y 8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2 = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m
Answer:
The two main variables in an experiment are the independent and dependent variable. An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.
At first sight it doesn't bode well. The key is in how firmly the protons and neutrons are held together. In the event that an atomic response produces cores that are more firmly bound than the firsts then vitality will be created, if not you should place vitality into make the response happen.
Answer:
<h2>0.87 atm </h2>
Explanation:
The new pressure can be found by using the formula for Boyle's law which is

Since we are finding the new pressure

From the question
2.47 L = 2470 mL
We have

We have the final answer as
<h3>0.87 atm</h3>
Hope this helps you
Explanation:
(a) It is known that relation between energy and mass is as follows.

where, E = energy
m = mass
c = speed of light =
m/s
As it is given that mass is
kg. So, putting the given values into the above formula as follows.

=
= 
Therefore, we can conclude that the energy produced by the reaction between one electron and one positron is
.
(b) When gamma ray photons are produced then they will have the same frequency. Relation between energy and frequency is as follows.
E =
..... (1)
where, h = plank's constant = 
= frequency
Also,
........ (2)
Hence, equating equations (1) and (2) as follows.
=
So,
= 
= 
Thus, we can conclude that the frequency is
.