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grandymaker [24]
3 years ago
9

In reality, energy conversion from burning fuel is never 100% efficient. Significant loss of energy due to heating occurs. If th

e generator were only 20% efficient (which is more realistic), how much energy in joules would be converted to electrical energy and how much would be lost to heat? (2 points)​
Chemistry
1 answer:
algol [13]3 years ago
6 0

Answer:

Electrical energy = 130000000 J and Heat energy = 520000000 J

Explanation:

Multiply the amount of joules from the last question (650000000) by .20 and .80. (Which are the percentages)

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What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
4 years ago
Therefore, the independent variable was<br> and the dependent<br> variable was
den301095 [7]

Answer:

The two main variables in an experiment are the independent and dependent variable. An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.

5 0
3 years ago
Read 2 more answers
How is the structure of atoms altered during fission and fusion?
Dmitriy789 [7]
At first sight it doesn't bode well. The key is in how firmly the protons and neutrons are held together. In the event that an atomic response produces cores that are more firmly bound than the firsts then vitality will be created, if not you should place vitality into make the response happen.
6 0
4 years ago
If 765 mL of a gas at 2.78 atm, has the volume Change to 2.47 L , What is the pressure of the
vampirchik [111]

Answer:

<h2>0.87 atm </h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question

2.47 L = 2470 mL

We have

P_2 =  \frac{765 \times 2.78}{2470}  =  \frac{2142}{2470}  \\  = 0.867206...

We have the final answer as

<h3>0.87 atm</h3>

Hope this helps you

3 0
3 years ago
The half-life of a positron is very short. It reacts with an electron, and the masses of both are converted to two gamma-ray pho
sp2606 [1]

Explanation:

(a)   It is known that relation between energy and mass is as follows.

            E = 2 \times mc^{2}

where,    E = energy

              m = mass

              c = speed of light = 3 \times 10^{8} m/s

As it is given that mass is 9.109 \times 10^{-31} kg. So, putting the given values into the above formula as follows.

             E = 2 \times mc^{2}

                       = 2 \times 9.109 \times 10^{-31} kg \times 3 \times 10^{8}m/s

                       = 1.638 \times 10^{-13} J

Therefore, we can conclude that the energy produced by the reaction between one electron and one positron is 1.638 \times 10^{-13} J.

(b) When gamma ray photons are produced then they will have the same frequency. Relation between energy and frequency is as follows.

                    E = h \times \nu   ..... (1)

where,     h = plank's constant = 6.626 \times 10^{-34} J.s

              \nu = frequency

Also,     E = 2 \times mc^{2} ........ (2)

Hence, equating equations (1) and (2) as follows.

                    h \times \nu = 2 \times mc^{2}        

So,    

6.626 \times 10^{-34} Js \times \nu = 1.638 \times 10^{-13} J

                           \nu = 1.236 \times 10^{20} Hz

Thus, we can conclude that the frequency is 1.236 \times 10^{20} Hz.

5 0
3 years ago
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