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kvv77 [185]
3 years ago
10

After oil is naturally refined underground, the only way that a viable deposit of hydrocarbons can form is if the oil encounters

some kind of
Chemistry
1 answer:
Arisa [49]3 years ago
8 0
After oil is naturally refined underground, the only way that a viable deposit of hydrocarbon can form is if the oil encounters some kind of trap.
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Are atoms of gold the same as antoms of oxygen? yes or no?​
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No they are not the same the are both di

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Does mercury have more protons and electrons than tin?
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Liquid waste that exits the body is _____________ and solid waste is ___________.
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Explanation:

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2 years ago
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For part one synthesis reactions The product of the reaction is MgO. Describe what you observed in the reaction then consider th
vazorg [7]

Answer:

2Mg+O_{2} \rightarrow 2MgO

Explanation:

<u>Synthesis reaction:</u>

In the synthesis reaction, two reactants combined to form a single product.

For example,

"A" and "B" are two reactants then combined to form a "AB" product.

The chemical reaction is as follows.

A+B \rightarrow AB

The product "MgO" is formed by magnesium reacts with oxygen to form Magnesium oxide.

The chemical reaction is as follows.

2Mg+O_{2} \rightarrow 2MgO

7 0
3 years ago
Complete the following reaction.<br> 14N+ on →?C+1H<br> 18C<br> 14<br> 1 C<br> 18C
CaHeK987 [17]

Answer: The complete reaction is as follows.

 ^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H

Explanation:

When nucleus of two or more atoms are bombarded together then it leads to the formation of new particles with new identity. This type of reaction are called nuclear reaction.

For example, ^{14}_{7}N + ^{1}_{0}n \rightarrow ?C + ^{1}_{1}H

Here, nitrogen atom when bombarded with a neutron then it is forming hydrogen and a carbon atom.

As total atomic mass on reactant side is (14 + 1) = 15

So, the atomic mass of carbon formed on product side is (15 - 1) = 14.

The number of protons holded by this carbon atom is (7 - 1) = 6.

Therefore, we can conclude that the complete reaction is as follows.

 ^{14}_{7}N + ^{1}_{0}n \rightarrow ^{14}_{6}C + ^{1}_{1}H

6 0
3 years ago
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