Answer:
Many of the pollen produced never reach eggs cells due to environmental factors
Explanation:
Coulomb's Law
Given:
F = 3.0 x 10^-3 Newton
d = 6.0 x 10^2 meters
Q1 = 3.3x 10^-8 Coulombs
k = 9.0 x 10^9 Newton*m^2/Coulombs^2
Required:
Q2 =?
Formula:
F = k • Q1 • Q2 / d²
Solution:
So, to solve for Q2
Q2 = F • d²/ k • Q1
Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9
Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)
Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)
Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)
Then, take the reciprocal of the denominator and start
multiplying
Q2 = 1080 • 1 Coulombs/297
Q2 = 1080 Coulombs / 297
Q2 = 3.63636363636 Coulombs
Q2 = 3.64 Coulumbs
Centripetal acceleration
#1
#2
Direction of force also towards centre
Answer:
Explanation:
So we want the speed to go from 25 m/s to 0 m/s in 170 m, but the time needs to incorporate the reaction time, so the slowing down will not start until .68 s pass. Or, in other words, the train will travel an extra 25 m/s * .68 s = 17 m. This means, instead of 170 m to slow down it has 153. Hopefully that makes sense. With this information we can use the equation vf^2-vi^2=2ad. If that equation is unfamiliar you need to get a better handle on your physics equations.
Anyway, let's plug in.
vf = 0 m/s
vi = 25 m/s
a is what we're trying to find
d = 153 m
vf^2-vi^2=2ad
a = (vf^2-vi^2)/(2d)
Can you handle figuring it out from there? or if there is something you don't understand let me know.
We'll find the car's speed first, and then use that to find the velocity.
Speed = (distance covered) / (time to cover the distance)
Speed = (240 miles) / (3 hours)
Speed = (240/3) · (miles/hours)
Speed = 80 mile/hour
Now to convert the units, we'll use
-- 1 mile = 1,609 meters
-- 1 hour = 3,600 seconds
(80 miles/1 hour) · (1,609 meter/1 mile) · (1 hour/3,600 second) =
(80 · 1,609 · 1) / (1 · 1 · 3,600) (mile · meter · hour / hour · mile · second) =
35.76 meter/second
Now, to make a velocity, all we need to do is to add the direction to the speed.
So the car's <em>velocity</em> is <em>80 mi/hr south</em>, or <em>35.76 meter/sec south</em> .