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Gemiola [76]
3 years ago
9

Please answer. give full explanation.

Physics
1 answer:
Ad libitum [116K]3 years ago
4 0
Work done=F *s*cos theta
Work done in this case can only be in the direction in which the electrons move.Thus cos theta is multiply to find the component of the force ( acting on an object doing work) which acts in the direction of propagation on movement of the object.Anyway,as in this case ,as magnetic field act only perpendicularly (at 90°) to electric fields(those are the electrons)no work is done.This is cause at 90°,there is no component of the magnetic field exiting of force in the direction of propagation of the electric field (electrons),as cos of 90 ° is 0, no work is done by the magnetic field.(as the whole product becomes zero regardless of the force or the displacement/distance
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A frog jumps vertically upward from a 20m tall building with an initial velocity of 8.1m/s. How high above the ground will the f
topjm [15]

Answer:

Explanation:

Consider the initial position of the frog (20 m above ground) as the reference position. All measurements are positive measured upward.

Therefore,

u = 10 m/s, initial upward velocity.

H = - 20 m, position of the ground.

g = 9.8 m/s², acceleration due to gravity.

Part (a)

When the frog reaches a maximum height of h from the reference position, its velocity is zero. Therefore

u² - 2gh = 0

h = u²/(2g) = 10²/(2*9.8) = 5.102 m

At maximum height, the frog will be 20 + 5.102 = 25.102 m above ground.

Answer: 25.1 m above ground

Part (b)

Let v = the velocity when the frog hits the ground. Then

v² = u² - 2gH

v² = 10² - 2*9.8*(-20) = 492

v = 22.18 m/s

Answer: The frog hits the ground with a velocity of 22.2 m/s

8 0
4 years ago
The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?
xxMikexx [17]

Answer:

Q = 675 [J]

Explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

Q=m*C_{p}*(T_{initial}-T_{final})

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

Q=25*0.9*(55-25)\\Q=675 [J]

4 0
3 years ago
A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?
Makovka662 [10]

Answer:

v=30 m/s

Explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

h =  \frac{1}{2}  \times g \times t {}^{2}

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s

3 0
3 years ago
The energy levels of a particular quantum object are -11.7 eV, -4.2 eV, and -3.3 eV. If a collection of these objects is bombard
gogolik [260]

To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.

By definition the energy balance is simply given by the change between the two states:

|\Delta E_{ij}| = |E_i-E_j|

Our states are given by

E_1 = -11.7eV

E_2 = -4.2eV

E_3 = -3.3eV

In this way the energy balance for the states would be given by,

|\Delta E_{12}| = |E_1-E_2|\\|\Delta E_{12}| = |-11.7-(-4.2)|\\|\Delta E_{12}| = 7.5eV\\

|\Delta E_{13}| = |E_1-E_3|\\|\Delta E_{13}| = |-11.7-(-3.3)|\\|\Delta E_{13}| = 8.4eV

|\Delta E_{23}| = |E_2-E_3|\\|\Delta E_{23}| = |-4.2-(-3.3)|\\|\Delta E_{23}| = 0.9eV

Therefore the states of energy would be

Lowest : 0.9eV

Middle :7.5eV

Highest: 8.4eV

8 0
4 years ago
In cats, short hair is dominant and long hair is recessive. If a cat has the genotype of hh, what type of hair will it have?
raketka [301]

Answer:

long hair

Explanation:

long hair = hh

short hair= HH

and medium= Hh

8 0
3 years ago
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