Let the salmon jump with speed v at an angle of 33.3 degree
So here we can find out the components of his velocity in x and y direction
now the horizontal displacement of the salmon is 3.15 m so he cover this horizontal distance with constant speed as there is no acceleration in x direction
here we can say
now in Y direction it is an accelerated motion as it is accelerated due to gravity
now we will plug in v*t = 3.76
now speed v is given by equation above
so here he must have to jump with minimum speed of 5.25 m/s
D=Vot+1/2at^2
In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2
acceleration=acceleration due to gravity=-9.8m/s^2
It falls - 22cm or -0.22m
We have - 0.22=1/2(-9.8)t^2
t^2=(-0.44)/(-9.8)
t=sqrt[0.44/9.8]
Answer:
Speed of the boat, v = 4.31 m/s
Explanation:
Given that,
Height of the bridge, h = 32 m
The model boat is 11 m from the point of impact when the key was released, d = 11 m
Firstly, we will find the time needed for the boat to get in this position using second equation of motion as :
Here, u = 0 and a = g
t = 2.55 seconds
Let v is the speed of the boat. It can be calculated as :
v = 4.31 m/s
So, the speed of the boat is 4.31 m/s. Hence, this is the required solution.
That depends on several things that we don't know.
A few of them are:
-- the size of the sample
-- what level of radioactivity was measured at the beginning
-- what's the unit of the 12.5
-- the half-life of the substance involved