At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m.
So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY.......
We apply v² = u² + 2as in the y direction only. Ignore x direction.
IN Y DIRECTION:
v² = u² + 2as
0 = u² - 2gh
u = √(2gh) (Sub in values at the very end)
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity)
So rearranging,
velocity = (velocity in y direction only) / sin 3°
= √(2gh)/sin 3°
= (√(2 x 9.8 x 0.33)) / sin 3°
= 49 m/s at 3° to the horizontal
Answer:
73.6 minutes
Explanation:
relative time = time interval / √(1 - observer velocity² / speed of light²)
we have relative time. we want time interval.
rearrange
time interval = relative time x √(1 - observer velocity² / speed of light²)
convert 85 mins into seconds
85 x 60 = 5100
1.5 x 10⁸ as a number is 150000000
for c = 299 792 458
time interval = 5100 x √(1 - 150 000 000² / 299 792 458²)
for c = 3 x 10⁸
time interval = 5100 x √(1 - 150 000 000² / 300 000 000²)
time interval = 5100 x 0.866
time interval = 4415.71
divide by 60 for back into minutes
time = 73.6 minutes
So, C = kE°A/d
putting the values,
C
= 3.8 × 8.85×10^(-12) × 3.14×1.5×1.5 × 10^(-6)/0.43 × 10^(-3)
so, 1.02 × 10^(-13)
so the most appropriate answer is 2 ...that is
1.4 × 10^(-13) ....answer !!
If you decrease the pressure of a fixed amount of gas, its volume will increase.
Answer:b) atoms
Explanation:which are in turn made up of protons, neutrons and electrons
