Answer: 313.24K
Explanation:
Given that:
Initial air pressure P1 = 210kPa
Initial Temperature T1 = 26°C
(Since, the SI unit of temperature is Kelvin, convert temperature in celsius to kelvin
26°C + 273 = 299K)
Final temperature T2 = ?
Final pressure P2 = 220kPa
Since, pressure and temperature are involved while volume is constant, apply the formula for pressure law
P1/T1 = P2/T2
210kPa/299K = 220kPa/T2
Cross multiply
210kPa x T2 = 220kPa x 299K
210 x T2 = 65780
T2 = (65780/210)
T2 = 313.24K
Thus, the temperature of the air in the tyre is 313.24K
Answer:
5.22 x 10^5 V
Explanation:
guessed on castle learning and got it right
Answer:
A
Explanation:
may i be marked as brnliest?
Answer:
wavelength= 1.05 × 10^ -46 m
Explanation:
the formula : λ= hc/E
where; "h" = Planck's constant [6.626 × 10^ -34]
c= speed of light [3.0 × 10^ 8]
you first have to convert the energy of the photon to Joules by dividing the constant by 1000
2.09 × 10^ -18 / 1000 = 2.09 × 10^ -21
then you replace you data into the equation
λ= 6.626 × 10^ -34 × 3.0 × 10^ 8 / 2.09 × 10 ^ -21
first multiply the Planck's constant and the speed of light then divide it by the energy which is in "Joules"
:. λ = 1.05 × 10^ -46
hope this helps