Answer:
a) The charge of the capacitor is 4.25x10⁻¹¹C
b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.
c) The potential difference across the plates is 18 V
d) The work is 7.64x10⁻¹⁰J
Explanation:
The capacitance of the capacitor is equal to:

A = 2 cm² = 0.0002 m²
d = 0.5 mm = 0.0005 m
Replacing:

a) The charge of the capacitor is equal to:
Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C
b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)
c) If distance is increased, we have:

The potential is:

d) The work done is equal to:

You can reason it out like this:
-- The car starts from rest, and goes 8 m/s faster every second.
-- After 30 seconds, it's going (30 x 8) = 240 m/s.
-- Its average speed during that 30 sec is (1/2) (0 + 240) = 120 m/s
-- Distance covered in 30 sec at an average speed of 120 m/s
= 3,600 meters .
___________________________________
The formula that has all of this in it is the formula for
distance covered when accelerating from rest:
Distance = (1/2) · (acceleration) · (time)²
= (1/2) · (8 m/s²) · (30 sec)²
= (4 m/s²) · (900 sec²)
= 3600 meters.
_________________________________
When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is
quite bogus, but entertaining nonetheless.
When the light turns green, Andy mashes the pedal to the metal
and covers almost 2.25 miles in 30 seconds.
How does he do that ?
By accelerating at 8 m/s². That's about 0.82 G !
He does zero to 60 mph in 3.4 seconds, and at the end
of the 30 seconds, he's moving at 534 mph !
He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
police department doesn't have a jet fighter plane to chase
cars with.
The error percentage in measuring the volume of the cylindrical box is 6.3 x 10⁻³ %
<h3>
Error percentage in measuring the volume of the cylinder</h3>
The total error percentage in measuring the volume of the cylinder is calculated as follows;
Volume of cylinder = πr²h
Volume of cylinder = π(0.03r)²(0.07h)
Volume of cylinder = (6.3 x 10⁻⁵)πr²h
Error in measuring the volume = 6.3 x 10⁻⁵ x 100% = 6.3 x 10⁻³ %
Learn more about percentage error here: brainly.com/question/5493941
#SPJ1
Answer:
D
Explanation:
It is important that we have two variables, Independent
and Dependant Variable.
The new charge on 7.0 µC ball is 10.5 µC and the new charge on 14.0 µC ball is 10.5 µC.
The change in the electrostatic force after the experiment is 0.031 N.
The given parameters:
- Charge on first metal ball, q1 = 7.0 µC
- Charge on second metal ball, q2 = 14 µC
- Distance between the charges, r = 1.9 m
<h3>Charge on each ball after experiment</h3>
After the experiment the charges will be at equilibrium, and the charge on each metal ball will be equal.


The new charge on 7.0 µC ball = 10.5 µC
The new charge on 14.0 µC ball = 10.5 µC
<h3>Change in electrostatic force</h3>

Lear more about electrostatic force here: brainly.com/question/17692887