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Sholpan [36]
3 years ago
5

Which statement correctly compares ultraviolet light or visible light? (A)Ultraviolet light has both shorter wavelengths and low

er radiant energy than visible light.
(B) Ultraviolet light has Both a higher frequency and a higher radiant energy than visible.
(C) Ultraviolet light has Both a higher frequency and longer wavelengths than visible light.
(D) Ultraviolet light has Both a lower frequency and longer wavelengths than visible light.
Physics
2 answers:
frozen [14]3 years ago
8 0

D is the correct answr my man

11Alexandr11 [23.1K]3 years ago
6 0

Answer:

d is correct

Explanation:

You might be interested in
A parallel plate capacitor filled with air with plate area 2-cm2 and plate separation of 0.5 mm is connected to a 12 V batter an
pashok25 [27]

Answer:

a) The charge of the capacitor is 4.25x10⁻¹¹C

b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.

c) The potential difference across the plates is 18 V

d) The work is 7.64x10⁻¹⁰J

Explanation:

The capacitance of the capacitor is equal to:

C=\frac{e_{0}A }{d}

A = 2 cm² = 0.0002 m²

d = 0.5 mm = 0.0005 m

Replacing:

C=\frac{8.85x10^{-12}*0.0002 }{0.0005} =3.54x10^{-12} F = 3.54pF

a) The charge of the capacitor is equal to:

Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C

b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)

c) If distance is increased, we have:

C=\frac{8.85x10^{-12}*0.0002 }{0.00075} =2.36x10^{-12} F=2.36pF

The potential is:

V=\frac{Q}{C} =\frac{42.48}{2.36} =18V

d) The work done is equal to:

W=VQ=18*42.48=764.6pJ=7.64x10^{-10} J

3 0
3 years ago
Read 2 more answers
Andy is waiting at the signal. As soon as the light turns green, he accelerates his car at a uniform rate of 8.00 meters/second2
Tatiana [17]
You can reason it out like this:

-- The car starts from rest, and goes 8 m/s faster every second.

-- After 30 seconds, it's going (30 x 8) = 240 m/s.

-- Its average speed during that 30 sec is  (1/2) (0 + 240) = 120 m/s

-- Distance covered in 30 sec at an average speed of 120 m/s

                                                                           =  3,600 meters .
___________________________________

The formula that has all of this in it is the formula for
distance covered when accelerating from rest:

       Distance = (1/2) · (acceleration) · (time)²

                       = (1/2) ·      (8 m/s²)     · (30 sec)²

                       =      (4 m/s²)          ·      (900 sec²)

                       =            3600 meters.

_________________________________

When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is
quite bogus, but entertaining nonetheless.

When the light turns green, Andy mashes the pedal to the metal
and covers almost 2.25 miles in 30 seconds.

How does he do that ?

By accelerating at 8 m/s².  That's about 0.82 G  !

He does zero to 60 mph in 3.4 seconds, and at the end
of the 30 seconds, he's moving at 534 mph ! 

He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
police department doesn't have a jet fighter plane to chase
cars with.
3 0
3 years ago
Shyam saw a cylindrical copper rod in his store room he realise that it can be used for various purposes it can be used as a flo
Misha Larkins [42]

The error percentage in measuring the volume of the cylindrical box is 6.3 x 10⁻³ %

<h3>Error percentage in measuring the volume of the cylinder</h3>

The total error percentage in measuring the volume of the cylinder is calculated as follows;

Volume of cylinder = πr²h

Volume of cylinder = π(0.03r)²(0.07h)

Volume of cylinder = (6.3 x 10⁻⁵)πr²h

Error in measuring the volume = 6.3 x 10⁻⁵ x 100% = 6.3 x 10⁻³ %

Learn more about percentage error here: brainly.com/question/5493941

#SPJ1

8 0
2 years ago
In a scientific experiment, how many independent variables should be tested at the same time? a none. Independent variables are
Volgvan

Answer:

D

Explanation:

It is important that we have two variables, Independent

and Dependant Variable.

8 0
3 years ago
Two small, identical metal balls with charges 7.0 µC and 14.0 µC are held in place 1.9 m apart. In an experiment, they are conne
Nostrana [21]

The new charge on 7.0 µC ball is 10.5 µC and the new charge on 14.0 µC ball is 10.5 µC.

The change in the electrostatic force after the experiment is 0.031 N.

The given parameters:

  • Charge on first metal ball, q1 = 7.0 µC
  • Charge on second metal ball, q2 = 14 µC
  • Distance between the charges, r = 1.9 m

<h3>Charge on each ball after experiment</h3>

After the experiment the charges will be at equilibrium, and the charge on each metal ball will be equal.

Q_t = q_1 + q_2\\\\Q_t = 7 \mu C + 14 \mu C\\\\Q_t = 21 \ \mu C

Q_1 = Q_2 = \frac{Q_t}{2} = \frac{21 \mu C}{2} = 10.5 \ \mu C

The new charge on 7.0 µC ball = 10.5 µC

The new charge on 14.0 µC ball = 10.5 µC

<h3>Change in electrostatic force</h3>

F_1 =  \frac{kQ_1Q_2}{r^2} \\\\F_1 = \frac{9\times 10^9}{1.9^2} (7 \times 10^{-6} \times 14 \times 10^{-6}) \ \\\\ F_1 =  0.244 \ N\\\\for \ new \ charges;\\\\F_2 =  \frac{kQ_1Q_2}{r^2} \\\\F_2 = \frac{9\times 10^9}{1.9^2} (10.5 \times 10^{-6} \times 10.5 \times 10^{-6}) \ \\\\ F_2 =  0.275 \ N\\\\\Delta F = F_2 - F_2\\\\\Delta F = 0.275 \ N \ - \ 0.244 \ N\\\\\Delta F = 0.031 \ N

Lear more about electrostatic force here: brainly.com/question/17692887

8 0
3 years ago
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