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AysviL [449]
3 years ago
12

I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?

Physics
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

The height from which the egg is dropped is <u>68.54 m</u>.

Explanation:

Given:

Initial velocity of egg is, u=0\ m/s(Dropped means initial velocity is 0)

Time taken is, t=3.74\ s

Acceleration experienced by egg is due to gravity, a=g=9.8\ m/s^2

The height from which the egg is dropped is, d=?

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

d=ut+\frac{1}{2}at^2

Plug in all the given values and solve for 'd'. This gives,

d=0+\frac{1}{2}\times 9.8\times (3.74)^2\\\\d=\frac{1\times 9.8\times 13.9876}{2}\\\\d=\frac{137.078}{2}\\\\d=68.54\ m

Therefore, the height from which the egg is dropped is 68.54 m.

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A 0.73-m aluminum bar is held with its length parallel to the east-west direction and dropped from a bridge. Just before the bar
Tasya [4]

Answer:

A)  B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West

Explanation:

A) For this exercise we must use the expression of Faraday's law for a moving body

            fem = -  \frac{d \phi }{dt}

            fem = - \frac{d (B l y}{dt}= - B l v- d (B l y) / dt = - B lv

            B = - \frac{fem}{l \ v}

we calculate

             B = - 7.9 10⁻⁴ /(0.73 20)

             B = 5.4 10⁻⁵ T

B) to determine which side of the bar is positive, we must use the right hand rule

the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.

Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West

4 0
3 years ago
Si está probando u motor para un nuevo modelo de coche ; este es capaz de pasar de 0 a 100 km/h en 7,5 segundos . Si el coche ti
RideAnS [48]

Answer:

La fuerza que realiza el motor es 2035 N.

Explanation:

Podemos encontrar la fuerza del motor usando la siguiente ecuación:

F = ma   (1)

En donde:

m: es la masa del coche = 550 kg

a: es la aceleración

Se puede calcular la aceleración mediante la siguiente ecuación cinemática:

v_{f} = v_{0} + at   (2)

En donde:

v_{f}: es la velocidad final del coche = 100 km/h

v_{0}: es la velocidad inicial del coche = 0

t: es el tiempo = 7,5 s

Resolviendo la ecuación (2) para "a" tenemos:

a = \frac{v_{f} - v_{0}}{t} = \frac{100\frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s} - 0}{7,5 s} = 3,70 m/s^{2}

Entonces, la fuerza es:

F = ma = 550 kg*3,70 m/s^{2} = 2035 N

Por lo tanto, la fuerza que realiza el motor es 2035 N.

Espero que te sea de utilidad!

7 0
3 years ago
What way would the balls fall? Top<br> Left<br> Right<br> Bottom
stira [4]
Each ball, when released, will fall toward the center of the big ball that everybody is standing on.

Another way to describe it:  Each ball, when released, will fall in the direction parallel to a line from the boy's head to his feet.

-- The ball held by the boy on top will fall toward the bottom of the picture.

-- The ball held by the boy on the right will fall toward the left side of the picture.

-- The ball held by the boy on the bottom will fall toward the top of the picture.

-- The ball held by the boy on the left will fall toward the right side of the picture.

In each case, the direction toward the center of the big ball that they're all standing on is the direction that each person calls "down".
3 0
4 years ago
4 properties of light
Neko [114]
-reflection and refraction of light
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-absorption of light
-polarization of light
3 0
3 years ago
A 100 kg bag of sand has a weight on 100 N. When dropped its acceleration is what?
Anettt [7]

Answer:

The acceleration of the bag of sand is 1\ m/s^2.

Explanation:

We have,

Mass of a bag of sand is 100 kg

Weight of the bag of sand is 100 N

It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :

F =ma

When it is dropped, a = g

g=\dfrac{F}{m}\\\\g=\dfrac{100}{100}\\\\g=1\ m/s^2

So, the acceleration of the bag of sand is 1\ m/s^2.

4 0
4 years ago
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