Question

I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?

Answer 1

Answer:

The height from which the egg is dropped is 68.54 m.

Explanation:

Given:

Initial velocity of egg is, $u=0\ m/s$(Dropped means initial velocity is 0)

Time taken is, $t=3.74\ s$

Acceleration experienced by egg is due to gravity, $a=g=9.8\ m/s^2$

The height from which the egg is dropped is, $d=?$

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

$d=ut+\frac{1}{2}at^2$

Plug in all the given values and solve for 'd'. This gives,

$d=0+\frac{1}{2}\times 9.8\times (3.74)^2\\\\d=\frac{1\times 9.8\times 13.9876}{2}\\\\d=\frac{137.078}{2}\\\\d=68.54\ m$

Therefore, the height from which the egg is dropped is 68.54 m.