Answer:
Horse/Speed
55 mph
rounded to the tenth? either 60 or 50
but 350 would stay like that i believe!
Explanation:
v = √ { 2*(KE) ] / m } ;
Now, plug in the known values for "KE" ["kinetic energy"] and "m" ["mass"] ;
and solve for "v".
______________________________________________________
Explanation:
_____________________________________________________
The formula is: KE = (½) * (m) * (v²) ;
_____________________________________
"Kinetic energy" = (½) * (mass) * (velocity , "squared")
________________________________________________
Note: Velocity is similar to speed, in that velocity means "speed and direction"; however, if you "square" a negative number, you will get a "positive"; since: a "negative" multiplied by a "negative" equals a "positive".
____________________________________________
So, we have the formula:
___________________________________
KE = (½) * (m) * (v²) ; to solve for "(v)" ; velocity, which is very similar to the "speed";
___________________________________________________
we arrange the formula ;
__________________________________________________
(KE) = (½) * (m) * (v²) ; ↔ (½)*(m)* (v²) = (KE) ;
___________________________________________________
→ We have: (½)*(m)* (v²) = (KE) ; we isolate, "m" (mass) on one side of the equation:
______________________________________________________
→ We divide each side of the equation by: "[(½)* (m)]" ;
___________________________________________________
→ [ (½)*(m)*(v²) ] / [(½)* (m)] = (KE) / [(½)* (m)]<span> ;
</span>______________________________________________________
to get:
______________________________________________________
→ v² = (KE) / [(½)* (m)]
→ v² = 2 KE / m
_______________________________________________________
Take the "square root" of each side of the equation ;
_______________________________________________________
→ √ (v²) = √ { 2*(KE) ] / m }
________________________________________________________
→ v = √ { 2*(KE) ] / m } ;
Now, plug in the known values for "KE" ["kinetic energy"] and "m" ["mass"];
and solve for "v".
______________________________________________________
Answer:
Current = 3 Amperes
Explanation:
Given the following data;
Quantity of charge = 6 C
Time = 2 seconds
To find how many amps are moving through this wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
6 = current * 2
Current = 6/2
Current = 3 Amperes
Answer: Force = Mass X Acceleration
F = 5 x 2
F = 10 N
Answer:
8.60 g/cm³
Explanation:
In the lattice structure of iron, there are two atoms per unit cell. So:
where 
an and A is the atomic mass of iron.
Therefore:
This implies that:
= 
Assuming that there is no phase change gives:
= 8.60 g/m³
