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snow_lady [41]
3 years ago
5

In a concave mirror, if an object is located between the center of curvature and the focal point, what is the best way to descri

be the image formed?
Real, inverted, and smaller than the object


Real, inverted, and larger than the object


light rays travel parallel to each other, no other image is formed.


Real, inverted, and the same size as the object.
Physics
2 answers:
DiKsa [7]3 years ago
5 0
The image formed in a concave mirror when an object is located between C and F is real, inverted, and larger than the object or magnified. Wherever the object may be between the center of curvature and focus, the concave mirror will always produce a magnified version of an object that is farther from the center of curvature. The image produced is real because light rays would converge to where the object is located.
kondaur [170]3 years ago
5 0

Answer:

Real, inverted, and larger than the object.

Explanation:

The image is reflected, therefore it would be inverted because it reflects and flips light. It would be larger and real because it reflects whatever is facing the mirror and would be closer reflecting the curvature.

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Answer:

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I think this is the ans

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iVinArrow [24]
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MaRussiya [10]
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3 0
3 years ago
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An object accelerates in a direction that is always perpendicular to its motion.what is the effect if any of the acceleration on
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Vector A has magnitude of 15.0 m/s and is 75° counter-clockwise up from the x-axis. What are the x- and y-components of the vect
LiRa [457]

Answer:

x component 3.88 y- component 14.488

Explanation:

We have given a vector A which has a magnitude of 15 m/sec which is at 75° counter-clock wise ( anti-clock wise) from x -axis which is clearly shown in bellow figure

Now x-component will be 15 cos75°=3.8822 ( as it makes an angle of 75° with x-axis )

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