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snow_lady [41]
3 years ago
5

In a concave mirror, if an object is located between the center of curvature and the focal point, what is the best way to descri

be the image formed?
Real, inverted, and smaller than the object


Real, inverted, and larger than the object


light rays travel parallel to each other, no other image is formed.


Real, inverted, and the same size as the object.
Physics
2 answers:
DiKsa [7]3 years ago
5 0
The image formed in a concave mirror when an object is located between C and F is real, inverted, and larger than the object or magnified. Wherever the object may be between the center of curvature and focus, the concave mirror will always produce a magnified version of an object that is farther from the center of curvature. The image produced is real because light rays would converge to where the object is located.
kondaur [170]3 years ago
5 0

Answer:

Real, inverted, and larger than the object.

Explanation:

The image is reflected, therefore it would be inverted because it reflects and flips light. It would be larger and real because it reflects whatever is facing the mirror and would be closer reflecting the curvature.

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Un automóvil viaja a la velocidad de 10 m/s. Se acelera Durante 12s y aumenta su velocidad hasta 70 m/s ¿Que aceleración experim
VladimirAG [237]

Answer:

Aceleracion = 5 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 10 m/s

Velocidad final = 70 m/s

Tiempo, t = 12 segundos

Para encontrar la aceleración;

Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.

Esto simplemente significa que la aceleración viene dada por la resta de la velocidad inicial de la velocidad final a lo largo del tiempo.

Por lo tanto, si restamos la velocidad inicial de la velocidad final y la dividimos por el tiempo, podemos calcular la aceleración de un objeto. Matemáticamente, la aceleración viene dada por la fórmula;

Aceleracion = \frac{final \; velocidad  -  inicial \; velocidad}{tiempo}

Sustituyendo en la fórmula, tenemos;

Aceleracion = \frac{70 - 10}{12}

Aceleracion = \frac{60}{12}

Aceleracion = 5 m/s²

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3 years ago
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<h2>B. Switch</h2>

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