Answer:
Width of the slit will be equal to 1.47 mm
Explanation:
We have given wavelength of the light
Distance D = 8 m
Distance between first minimum dark fringe and the central maximum is 2 mm
So
We have to find the width of the slit
For the first order wavelength is equal to , here a width of slit
So
So width of the slit will be equal to 1.47 mm
Answer:
628.022466 N
8.61 m/s
Explanation:
m = Mass
= Coefficient of friction
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Magnitude of frictional force is 628.022466 N
Initial speed of the player is 8.61 m/s
Answer:
Explanation:
The gravitational pull between two object is given by:
Where M and m are the masses of the object, r is the distance between the masses and G = 6.67× 10⁻¹¹ m³kg⁻¹ s⁻² is the gravitational constant.
We have to calculate the net force on Earth due to Venus, Jupiter and Saturn when they are in one line. It means when they are the closest distance.
Mass of Earth, Me = 5.98 × 10²⁴ kg
Mass of Venus, Mv = 0.815 Me
Mass of Jupiter, Mj = 318 Me
Mass of Saturn, Ms = 95.1 Me
closest distance between Earth and Venus, rv = 38 × 10⁶ km = 0.25 AU
closest distance between Jupiter and Earth, rj = 588 × 10⁶ km = 3.93 AU
closest distance between Earth and Saturn, rs = 1.2 × 10⁹ km = 8.0 AU
where 1 AU = 1.5 × 10¹¹ m
Inserting the values: