Answer:
x = 41.28 m
Explanation:
This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.
Let's start by using trigonometry to find the initial velocity
cos 25 = v₀ₓ / v₀
sin 25 = Iv_{oy} / v₀
v₀ₓ = v₀ cos 25
v_{oy} = v₀ sin 25
v₀ₓ = 22 cos 25 = 19.94 m / s
v_{oy} = 22 sin 25 = 0.0192 m / s
let's use movement on the vertical axis
y = y₀ + v_{oy} t - ½ g t²
when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m
0 = 21 + 0.0192 t - ½ 9.81 t²
4.905 t² - 0.0192 t - 21 = 0
t² - 0.003914 t - 4.2813 =0
we solve the quadratic equation
t = 
t = 
t₁ = 2.07 s
t₂ = -2.067 s
since time must be a positive scalar quantity, the correct result is
t = 2.07 s
now we can look up the distance traveled
x = v₀ₓ t
x = 19.94 2.07
x = 41.28 m
The velocity of penguin as he ends where he started was 0 m/s.
<h3>What is displacement?</h3>
Displacement is the length of straight line joining the initial and final position of the body.
Given is a penguin who waddled 8 m uphill before sliding back down to its friends in 2 seconds.
We know that the velocity is the rate of change of displacement with respect to time. Mathematically -
v = dx/dt
dx = v dt
∫dx = ∫v dt
Δx = vΔt
v = Δx/Δt
Now, the displacement of the penguin will be = Δx = 8 - 8 = 0
Then, its velocity will be -
v = 0/Δt = 0
Therefore, the velocity of penguin as he ends where he started was 0 m/s.
To solve more questions on kinematics, visit the link below-
brainly.com/question/27200847
#SPJ1
The amount of heat needed to increase the temperature of a substance by
is given by
where
m is the mass of the substance
the specific heat capacity
the increase in temperature
In our problem, the mass of the water is m=750 g, the specific heat is
and the amount of heat supplied is
, so if we re-arrange the previous formula we find the increase in temperature of the water:
<span>Now that you know the time to reach its maximum height, you have enough information to find out the initial velocity of the second arrow. Here's what you know about it: its final velocity is 0 m/s (at the maximum height), its time to reach that is 2.8 seconds, but wait! it was fired 1.05 seconds later, so take off 1.05 seconds so that its time is 1.75 seconds, and of course gravity is still the same at -9.8 m/s^2. Plug those numbers into the kinematic equation (Vf=Vi+a*t, remember?) for 0=Vi+-9.8*1.75 and solve for Vi to get.......
17.15 m/s</span>
