All categories

3 years ago

The density of benzene at 15 ∘c is 0.8787 g/ml. calculate the mass of 0.1000 l of benzene at this temperature.

Chemistry

2 answers:

Andrews [41]3 years ago

8 0

V=0,1 l=100 ml
m=p*V=0,8787*100=87,87g

VladimirAG [237]3 years ago

4 0

Answer: The mass of benzene is 87.87 grams

Explanation:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of benzene = $0.8787g/ml$

mass of benzene = ?

Volume of benzene = 0.1000L = 100ml $1L=1000mL$

Putting values in above equation, we get:

$0.8787g/ml=\frac{\text{Mass of benzene}}{100ml}$

Mass of benzene = 87.87g

Hence, the mass of benzene is 87.87 grams

You might be interested in

George Washington Carver received _____ from God during early morning walks in the woods.?

BabaBlast [244]

Answer:

1. Guidance

2. Inspiration

I think this is right hope it helps

8 0

3 years ago

Answer Quickly : Define and compare boiling points, melting points, and freezing points.

juin [17]

Boiling point is the temperature at which a substance begins to change to a gas. Melting point is the temperature at which a substance begins to turn into a liquid. And freezing point is the temperature at which a substance begins turning into a solid.

3 0

3 years ago

The concentration of a saturated BaCl2 solution is 1.75 M (mol/liter) and the concentration of a saturated Na2SO4 solution is 2.

Kitty [74]

Answer:

a) The theoretical yield is 408.45g of $BaSO_{4}$

b) Percent yield = $\frac{realyield}{408.45g}*100$

Explanation:

1. First determine the numer of moles of $BaCl_{2}$ and $Na_{2}SO_{4}$ .

Molarity is expressed as:

M= $\frac{molessolute}{Lsolution}$

- For the $BaCl_{2}$

M= $\frac{1.75molesBaCl_{2}}{1Lsolution}$

Therefore there are 1.75 moles of $BaCl_{2}$

- For the $Na_{2}SO_{4}$

M= $\frac{2.0moles[tex]Na_{2}SO_{4}$ }{1Lsolution}[/tex]

Therefore there are 2.0 moles of $Na_{2}SO_{4}$

2. Write the balanced chemical equation for the synthesis of the barium white pigment, $BaSO_{4}$ :

$BaCl_{2}+Na_{2}SO_{4}=BaSO_{4}+2NaCl$

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the $BaCl_{2}$ :

$\frac{1.75}{1}=1.75$

- For the $Na_{2}SO_{4}$ :

$\frac{2.0}{1}=2.0$

As the $BaCl_{2}$ is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

$1.75molesBaCl_{2}*\frac{1molBaSO_{4}}{1molBaCl_{2}}*\frac{233.4gBaSO_{4}}{1molBaSO_{4}}=408.45gBaSO_{4}$

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield = $\frac{realyield}{theoreticalyield}*100$

Percent yield = $\frac{realyield}{408.45g}*100$

The real yield is the quantity of barium white pigment you obtained in the laboratory.

7 0

3 years ago

Information collected through our five senses: sight, hearing,

lozanna [386]

Answer:

yes

Explanation:

The five senses: sight, hearing,

taste, smell, and touch can be extended with instruments

5 0

3 years ago

An inventor claims to have devised a closed cyclic engine which exchanges heat with cold and hot reservoirs at 25 and 350 ◦C, re

kati45 [8]

Explanation:

The given data is as follows.

$T_{c} = 25^{o}C$ , $T_{h} = 350^{o}C$

Work produced per kJ of heat extracted from hot reservoir = 0.45 kJ = Efficiency

If the device is Carnot cycle then its efficiency will be maximum and its value will be equal to $[1 - (\frac{T_{c}}{T_{h}} )]$

Using this relation we will calculate the efficiency as follows.

Efficiency = $[1 - (\frac{T_{c}}{T_{h}} )]$

= $1 - (\frac{25}{350})$

= 0.928

Hence, it means that this type of device is possible and the claim is also believable.

7 0

3 years ago