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2 years ago

Can someone please help me with this?

Chemistry

2 answers:

kolbaska11 [484]2 years ago

8 0

<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2 />

$\huge\boxed{Option C}$

<h2>_____________________________________</h2><h2>IONIC BOND:</h2>

Ionic bond is a type of bond which is formed between metals and non-metals. The group which provide the Metal are IA and IIA i.e. S block elements. The group which mostly provide non-metal is VII A i.e. halogens. The Metals give up their ONLY Valance shell electron which is accepted by the Non-metal. This results in formation of ions, The Metals gets the positive charge thus called cation and The non-metal gets a negative charge thus called anion. These Positive and Negative ion attract each other resulting in the formation of IONIC BOND.

The Ionic bond is formed between The metal and non metal because, the metals have low ionization energy due to which the valence shell is ejected out easily, and The Non-Metals have high electron affinity which means that they attract an electron with greater force because they need one electron to complete their octet.

<h2>_____________________________________</h2><h2>Question:</h2>

Question has given two atoms Potassium and chlorine. Potassium(Group 1) is metal, Chlorine(Group 7) is non metal. As you can se that there is only one electron in the outer shell of Potassium "K" and Chlorine need only one electron to complete its outer shell so Potassium will give its electron to Chlorine. Due to this reason K will become positive and Cl will become negative and they will both attract eachother forming ionic bond.

So the answer is Option C: Electron will be transferred from the potassium to the chlorine atom.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

yaroslaw [1]2 years ago

3 0

Answer:

Lonic.an electron will be transferred from potassium to the chlorine atom

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Lina20 [59]

Answer:

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2 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

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3 years ago

Based on the molecular formula, determine whether each compound is an alkane, alkene, or alkyne. (Assume that the hydrocarbons a

topjm [15]

Answer:

a. alkyne

b. alkane

c. alkyne

d. alkene

Explanation:

The general formula for each class of compound is given below

Alkane: $C_nH_{2n+2}$

Alkene: $C_nH_{2n}$

Alkyne: $C_nH_{2n-2}$ (assuming single multiple bonds)

Now let us classify according to the above formulas:

a. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

b. It has two hydrogen atoms more than the two times of carbon atoms hence, it's alkane

c. It has two hydrogen atoms less than the two times of carbon atoms hence, it's alkyne

d. It has hydrogen atoms two times of carbon atoms hence, it's alkene

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2 years ago

Read 2 more answers

Which of the following is the Arrhenius definition of an acid?

castortr0y [4]

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2 years ago

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gladu [14]

Answer:

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Explanation:

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