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grandymaker [24]
4 years ago
10

What do you think would happen if a solid were exposed to extremely cold temperatures, or if a gas were exposed to extremely hot

temperatures?
Chemistry
1 answer:
grandymaker [24]4 years ago
8 0

At high temperature the gas would diffuse out as the pressure increases and at extremely low temperature the solid becomes compact.

Explanation:

The states of matter largely depends on the temperature. Any substance when crosses the threshold temperature its phase changes.

When temperature is low the motion of molecules is also low and internal energy also gets low. Solid have tendency of settling in low energy level and have highly compact molecules. At low temperature the solid would compress as molecules would be highly condensed.

Gas in the nature has its molecules quite far apart in matter. According to Kinetic theory of gases the increase in temperature causes rapid collisions of the gas molecule as the kinetic energy of molecules increases. The greater force of collision would cause increase in pressure of the container and increased diffusion rate.

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In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol
zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

<u>Step 1:</u> Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

<u>Step 2: </u>The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

<u>Step 3:</u> mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0
4 years ago
Which of the following statements correctly explains the motion of atoms and molecules within the different states of matter? *
sineoko [7]

Answer:

The correct answer is : The particles within all three states of matter are constantly moving.

Explanation:

The particles in the solid, liquid and gaseous states are in motion. In the latter is where they present greater movement and high kinetic energy, then follow the liquid state and finally the solid where the movement is more restricted (in this case, the particles vibrate).

5 0
3 years ago
Read 2 more answers
Which of the following is true? A). An indicator is not pH sensitive. B). The equivalence point...
Pepsi [2]

Answer:

B). The equivalence point is where the amount of acid equals the amount of base during any add-base titration.

Explanation:

Equivalence point -

During the process of titration of the neutralization reaction , like acid - base reaction .

In the titration process , the equivalence point is the point , when the amount of acid is equal to the amount of base .

In indicator used for th process is pH sensitive ,

It is not always necessary to have pH = 7 at the equivalence point ,

The titration curve is plotted for the pH v/s base .

Hence , from the given options , the correct statement is ( B ) .

8 0
4 years ago
What equipment might you use to find the SHC of a material? Need to know the answer ASAP PLZ
algol [13]
Theses can include the power supply circuit a joule meter to measure the energy transferred which makes the calculations a lot easier.
4 0
3 years ago
5. Balance the following reactions using either the oxidation number method or the half-reaction
stich3 [128]

The balanced reaction equations are;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

<h3>What is a balanced redox reaction?</h3>

A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.

Let us now write the balanced reaction equations one after the other. Thus;

a) 4 NaClO + H2S → 4 NaCl + H2SO4

b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O

Learn more about redox reaction:brainly.com/question/13293425

#SPJ1

7 0
2 years ago
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